3 years ago

What does the exterior angle of a triangle add up to?

Mathematics

1 answer:

MissTica3 years ago

8 0

An exterior angle of a triangle is equal to the sum of the opposite interior angles.
here is an example above.

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If <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bdy%7D%7Bdt%7D%20%3Dky" id="TexFormula1" title=" \frac{dy}{dt} =ky" alt=" \frac

sladkih [1.3K]

This ODE is separable; we have

$\dfrac{\mathrm dy}{\mathrm dt}=ky\implies\dfrac{\mathrm dy}y=k\,\mathrm dt$

Integrating both sides gives a general solution of

$\ln|y|=kt+C\implies y=e^{kt+C}=Ce^{kt}$

B is the only choice that is applicable.

4 0

3 years ago

What is 1/5 x 35 ? thankyou :D

Aleksandr-060686 [28]

Answer:

you can alway convert the fraction to a decimal so it'll be

1/5(1 divided by 5)=0.2

0.2*35=7

7 0

3 years ago

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This one is number 6

iren2701 [21]

I’m not entirely sure, but i do think it could be B.

5 0

2 years ago

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PLEASE SOLVE THIS FOR ME ITS DUE TOMORROW Find an expression for the missing dimension.

denis-greek [22]

Answer:

The missing length is 2x+5

Step-by-step explanation:

Given equation of volume of cuboid is V= $2x^{3} +17x^{2} +46x+40$

Figure show that

Length of cuboid is ?

Width of cuboid is (x+4)

Height of cuboid is (x+2)

The volume of cuboid is given by

V=Length x Width x Height

Let Length be (bx+a)

The volume of cuboid will be

$V=(bx+a)(x+4)(x+2)$

$V=(bx+a)[x^{2}+4x+2x+8 ]$

$V=bx[x^{2}+6x+8]+a[x^{2}+6x+8]$

$V=[bx^{3}+6bx^{2}+8bx]+[ax^{2}+6ax+8a]$

$V=[bx^{3}+(6b+a)x^{2}+(8b+6a)x+8a]$

On comparing coefficient with given equation of volume

We get,

b=2 and 8a=40

Therefore, the value of a is 5 and b is 2

Thus, The missing length is bx+a=2x+5

7 0

3 years ago

If KM is drawn on this quadrilateral, what will be its length ???

torisob [31]

It should be 18 units

8 0

3 years ago

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