I believe it's Line y=-x+2 and y=3x+1 intersect the y-axis. From what I've gathered, they are parallel lines, and both are set on the y-axis.
Answer:
There is one solution
Step-by-step explanation:
2x + y = -1
8x + 3y = -2
Multiply the first equation by -4
-8x -4y = 4
Then add the equations together to eliminate x
-8x -4y = 4
8x + 3y = -2
--------------------
-y = 2
Multiply by -1
y =-2
Now find x
2x+y =-1
2x+-2 =-1
Add 2 to each side
2x-2+2=-1+2
2x=1
Divide by 2
x = 1/2
The distance between any point (x0,y0) on the parabola and the focus (m,n) is the same as the distance between (x0,y0) and the directrix line ax+by+c. The distance between (x0,y0) and focus (a,b) is \sqrt((x-m)^2+(y-n)^2). The distance between (x0,y0) and ax+by+c is |ax0+by0+c|/\sqrt(m^2+n^2). Equalize these two expressions.
Answer: y
= 3/2x+4 if you need to write it in slope intercept form and please give brainliest i will appreciate it.
