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3 years ago

Selecting 5 students to participate in a math contest would require the calculating of a permutation or combination?

Mathematics

1 answer:

Maslowich3 years ago

3 0

Selecting 5 students to participate in a math contest would require combinations.

SOLUTION:

given that, Selecting 5 students to participate in a math contest would require the calculating of a permutation or combination?

So, we need to differentiate between permutations and combinations.

Permutations - In mathematics, permutation is the act of arranging the members of a set into a sequence or order

Combinations - In mathematics, a combination is a selection of items from a collection, such that the order of selection does not matter.

So, now, for our math test, we just require students but not in an order nor with arrangements.

Hence, selecting 5 students to participate in a math contest would require combinations.

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joe runs 8.75 times around a track in 1,125.803 seconds. If one lap around the track is 420.3 meters, which is the best estimate

nikklg [1K]

8.75 x 420.3 = 3677.625 m
3677.625/1125.803 = 3.266668 ft/sec

7 0

4 years ago

How many solutions does this equation have? 6x-2=6x+7

Anon25 [30]

None, the equation 6x - 2 = 6x + 7 does not have any solutions.

<h3>What is an algebraic equation? </h3>

An algebraic equation is an equation that consists of numbers and variables. To solve the variables, there is a need to make use of some or all of the arithmetic operations such as:

Addition
Subtraction
Division, and
Multiplication

From the given equation:

6x - 2 = 6x + 7

Collect like terms

6x - 6x -2 - 7 = 0

0 - 9 = 0

Since there is no variable to solve for in the equation, we can conclude that the equation does not have any solutions.

Learn more about algebraic equations here:

brainly.com/question/4344214

6 0

3 years ago

Read 2 more answers

1/3(y - 2) -5/6 (y + 1) =3/4 (y - 3) - 2

Nataly [62]

Answer:

$y=\frac{11}{5}$

Step-by-step explanation:

Given expression

$\frac{1}{3}(y-2)-\frac{5}{6}(y+1)=\frac{3}{4}(y-3)-2$

To solve for $y$ for the given expression.

Solution:

We multiply each term with the least common multiple of the denominators of the fraction in order to remove fractions.

The multiples of the denominators are:

3 = 3,6,9,12,15

6 = 6,12

4 = 4,8,12

The least common multiple = 12.

Multiplying each term with 12.

$12.\frac{1}{3}(y-2)-12.\frac{5}{6}(y+1)=12.\frac{3}{4}(y-3)-2(12)$

$4(y-2)-10(y+1)=9(y-3)-24$

Using distribution.

$4y-8-10y-10=9y-27-24$

Simplifying.

$-6y-18=9y-51$

Adding $6y$ both sides.

$-6y+6y-18=9y+6y-51$

$-18=15y-51$

Adding 51 both sides.

$-18+51=15y-51+51$

$33=15y$

Dividing both sides by 15.

$\frac{33}{15}=\frac{15y}{15}$

$\frac{33}{15}=y$

Simplifying fractions.

$\frac{11}{5}=y$

∴ $y=\frac{11}{5}$ (Answer)

7 0

3 years ago

Can someone

Karo-lina-s [1.5K]

$804.2\:ft^{2}$

Step-by-step explanation:

$A=4 \pi r^{2}$

We are given D = 16 ft, which means that r = (1/2)D = 8 ft. Therefore, the surface area of the sphere is

$A=4 \pi (8 ft)^{2} = 804.2\:ft^{2}$

7 0

3 years ago

Determine what type of model bet fits the given situation: Every day, half a bacteria population dies. A. Linear B.quadratic C.

makvit [3.9K]

Answer:

Exponential

Step-by-step explanation:

Starter:

According to the title:

"Every day, half a bacteria population dies."

Exponential: y = ab^x ( b > 0 , b ≠ 1)

So the answer is C.

Calculations:

An exponential model is of the form y = a • b^t.

If you start with population of 500 million bacteria

t = 0

so 500 million = a • b^0 = a

Since every day half the population dies then in 1 day population will be 250 million

so a = 500 million, y = 250 million and t = 1

250 million = 500 million • b^1

b = 0.5

Therefore your equation would be

y = 500 million (or whatever the pop) • 0.5^t

Where t = number of days

This could also be written in exponential form ( e = 2.73)

4 0

2 years ago