The answer should be A. In order to solve these half-life problems, I encourage you to find an algebra calculator online, and plug in these numbers. The remaining grams goes in front, so 3.
The entire equation should look something like 3 = 15(1/2)^t/4.95
The 4.95 represents how long it takes before the sample halves, t is your answer, 1/2 represents the value halving every 4.95 hours, 15 is the initial sample size, and 3 is the end result that remains.
The overall answer should be about 11.5 hours, as per an algebra calculator.
Hope this helps solve any other similar problems
Here you go
2•k+10
(10•k)+(10•2)
is that in the answers? If not, do not put it in!
Answer:
![(e^{-1})^{-3}=e^{3}](https://tex.z-dn.net/?f=%28e%5E%7B-1%7D%29%5E%7B-3%7D%3De%5E%7B3%7D)
Step-by-step explanation:
Suppose
1) ![(e^{-1})^{-3}](https://tex.z-dn.net/?f=%28e%5E%7B-1%7D%29%5E%7B-3%7D)
2) By the Exponents rule, the power of a power is the same as the product of the exponents
![(a^{b})^{c}=a^{bc}](https://tex.z-dn.net/?f=%28a%5E%7Bb%7D%29%5E%7Bc%7D%3Da%5E%7Bbc%7D)
So:
![(e^{-1})^{-3}=e^{3}](https://tex.z-dn.net/?f=%28e%5E%7B-1%7D%29%5E%7B-3%7D%3De%5E%7B3%7D)
I think its A!! But im not sure
171 because first u minus 180 from 123 then you times that by 3