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Oliga [24]
3 years ago
10

You want to use a plasmid to transform an E. coli cell with a cry toxin gene from Bacillus thuringiensis in order to express the

toxin in E. coli. In addition to the gene of interest, what other elements must be included on the plasmid? Select all that apply. A gene encoding an E. coli-specific DNA polymerase. An origin of replication. A selectable marker (e.g., a gene encoding antibiotic resistance). A promoter allowing the expression of the cry gene in an E. coli host.
Biology
1 answer:
alexandr402 [8]3 years ago
6 0

Answer:

1) An origin of replication.

2) A selectable marker (e.g., a gene encoding antibiotic resistance).

Others are not necessary.

Explanation: In genetic engineering, three (3) things are responsible for manipulating nucleic acids, they are: plasmid, an origin of replication, and a selectable marker.

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4 years ago
How many bacteria would there be if 500 bacteria underwent fission every 20 minutes for an hour?
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Answer:

hjftjir?urififukfjf

Explanation:

Genel bilgi toplama sistemi yani GBT, ülkemizde, İçişleri Bakanlığı'na bağlı olarak “Adli Sicil Yönetmeliği” ile uygulanan bir veri toplama uygulamasıdır. ... Sistem, mahkeme kararı ya da hakkında adli karar olmadan değiştirilmesi mümkün olmayan verileri içermektedirGenel bilgi toplama sistemi yani GBT, ülkemizde, İçişleri Bakanlığı'na bağlı olarak “Adli Sicil Yönetmeliği” ile uygulanan bir veri toplama uygulamasıdır. ... Sistem, mahkeme kararı ya da hakkında adli karar olmadan değiştirilmesi mümkün olmayan verileri içermektedirGenel bilgi toplama sistemi yani GBT, ülkemizde, İçişleri Bakanlığı'na bağlı olarak “Adli Sicil Yönetmeliği” ile uygulanan bir veri toplama uygulamasıdır. ... Sistem, mahkeme kararı ya da hakkında adli karar olmadan değiştirilmesi mümkün olmayan verileri içermektedir

3 0
3 years ago
A geneticist is trying to recreate a strand of DNA from a crime scene investigation. The strand of DNA recovered from the scene
algol13

Answer:

475

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The strand is only made up of Adenine, Thymine, Cytosine and Guanine. There will be the same number of Adenine as there are Thymine and the same number of Cytosine as there are Guanine.

We know there are 425 Thymine. This means there are also 425 Adenine. Therefore, you would subtract 850 (425x2) from 1800 to find the amount of Cytosine and Guanine left, which is 950.

Out of the 950, half will be Cytosine and half Guanine. 950/2 is 475.

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