7.1
Use the formula of a circle. The radius is 1.5 and squared that is 2.25. Multiply that by 3.14 for your answer.
<u>Answer with explanation:</u>
As per given , we have
A sample of 50 gribbles finds an average length of 3.1 mm with a standard deviation of 0.72.
i.e. n= 50
Degree of freedom = n-1=49


The point estimate of the population mean is equals to the sample mean.
i.e. The best estimate for the length of gribbles= 3.1 mm
Also, population standard deviation is unknown , then the confidence interval would be :

For df= 49 and significance level of 0.05 , the t- value (using t-distribution table) would be :

Now, Margin of error : 

95% confidence interval : 


Therefore, the function is not differentiable at x = 1.

Therefore, the function is not differentiable at x = 0.
Step-by-step explanation:
Number of boxes that will fit =2340
Step-by-step explanation:
The shipping box volume can be calculated by the formula V = Lxwxh ,where L ,w ,h are length ,width and height of the box.
The length of the shipping box =3\frac{3}{4} =\frac{15}{4} ft.
Width = 3 ft.
Height =3\frac{1}{4} =\frac{13}{4} ft.
Volume of shipping box =\frac{15}{4} .3 .\frac{13}{4} =\frac{585}{16} = 36.6 ft.cubic ft.
Volume of shipping box can also be calculated by multiplying base area with the height of box.
Base area of box = \frac{15}{4} .3=\frac{45}{4} square ft.
Volume of box = base area x height =\frac{45}{4} .\frac{13}{4} = 36.6 cubic ft.
Volume of packing cubes =\frac{1}{4} .\frac{1}{4} .\frac{1}{4} =\frac{1}{64} cubic ft.
Number of fish boxes that will fit in the shipping box = volume of shipping box ÷ volume of fish food box = 36.6 ÷ \frac{1}{64} =2340 .