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gladu [14]
3 years ago
13

compare the right-hand and left-hand derivatives to show that the function is not differentiable at the point P. find all points

where f is not differentiable. (graph attached)

Mathematics
1 answer:
Softa [21]3 years ago
3 0
f(x)=  \left \{ {{ \sqrt{x} } \atop {2x-1}} \right. 
\\
\\ f'(x)=  \left \{ {{  \frac{1}{2\sqrt{x}} } \atop {2}} \right. 
\\
\\  f'(1)=  \left \{ {{  \frac{1}{2}} \atop {2}} \right. 
\\
\\ f'(1^-) \neq f'(1^+)

Therefore, the function is not differentiable at x = 1.

f(x)= \sqrt{x} 
\\
\\f'(x)= \frac{1}{2 \sqrt{x} } 
\\
\\f'(0)=\frac{1}{2 \sqrt{0} } = \infty

Therefore, the function is not differentiable at x = 0.
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Answer:

The total sale price that Gechina paid was $5,274.71.

Step-by-step explanation:

Given that Gechina Galvez shopped at a department store during the end-of-summer sale in which all luggage was marked down 35 percent, and she purchased a suitcase that regularly sells for $74.95, a garment bag that regularly sells for $8,000, and a tote bag that regularly sells for $39.99, in order to know the total sale price, the following calculation has to be made:

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8,114.94 x 0.65 = X

5,274.71 = X

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Answer:

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Step-by-step explanation:

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defon

Answer:

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Step-by-step explanation:

I got the answer by multiplying 5.301 by 107.So then I got 567.207.

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