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Ber [7]
3 years ago
7

What is the value of mQSR?

Mathematics
1 answer:
Nat2105 [25]3 years ago
7 0

Answer:

There is no M but I think that the value is 15 degrees

Step-by-step explanation:

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2 years ago
Thanks in advance for the answer
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2^{-2} =  \frac{1}{2^{2}} = \frac{1}{4} 


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3 years ago
H=255-21t-16t^2<br><br> PLEASE HELP!!
Colt1911 [192]

Answer:

3.15 seconds is the answer.

<u>Explanation</u>

when the ball touches the ground, h =0

hence,

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t=   \frac{ - b± \sqrt{ {b }^{2}  - 4ac} }{2a} \\  \\ t=   \frac{ - 21± \sqrt{ {21}^{2}  - 4 \times 16 \times  - 225} }{2 \times 16} \\  =  \frac{ - 21 ± \sqrt{441 - ( - 14400)} }{32} \\  =  \frac{ - 21± \sqrt{14841} }{32}  \\  =  \frac{ - 21±121.82}{32}  \\  \\ t =   \frac{ - 21 + 121.82}{32}  \: or \:  \: t =  \frac{ - 21 - 121.82}{32}  \\ t = 3.15 \:  \: or \:  \: t =  - 4.46

time cannot be negative, hence t = -4.46 can be avoided

The ball takes 3.15 seconds to hit the ground.

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3 years ago
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