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3 years ago

(6x^3 + 4x^2 + 2x) ÷ 2xAnswer fast plz..

Mathematics

2 answers:

kow [346]3 years ago

4 0

$\large\underline{\sf{Solution-}}$

$\textsf{Given expression;}\\$

$\sf{( {6x}^{3} + {4x}^{2} + 2x) \div 2x} \\$

$\sf \longmapsto \frac{ {6x}^{3} + 4 {x}^{2} + 2x}{2x} \\$

$\sf \longmapsto \frac{ {6x}^{3} }{2x} + \frac{4 {x}^{2} }{2x} + \frac{2x}{2x} \\$

$\sf \longmapsto \frac{ {6 \times x \times x \times x} }{2 \times x} + \frac{4 \times x \times x}{2 \times x} + \frac{2 \times x}{2 \times x} \\$

$\sf \longmapsto (3 \times x \times x) + (2 \times x) + 1 \\$

$\sf \longmapsto {3x}^{2} + 2x + 1 \: \: \: \red{ Ans.} \\$

$\bf{Read \: more:} \\$

-32x^4 ÷ 8x^2 Solve urgent plz..

brainly.com/question/25452595

Phoenix [80]3 years ago

3 0

refer to the attachment okay

mark me a brainlist answer I need only 1

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Hi :) I need help with q8 , new to this so I’m not sure how to solve it. Thank you sm :))

Marat540 [252]

Step-by-step explanation:

for part a

initial means starting point and starting point is always 0

so the question means number of thousands of bacteria in 0 hours, your n being the number of hours. so in part a u will simply just put 0 as n in equation

2^(0+3)

2³=8 thousands of bacteria

in part b

2^(n+3) means total number of bacteria

2^(n-1) is number of groups

its asking for number of bacteria in each group

so u will simply divide number of bacteria by groups

its like u have 30 candies and there are 5 groups and they ask u to find number of candies in each group so u simply divide 30 by 5

so 2^(n+3)/2^(n-1)

base is same so powers will subtract since there is division sign

2^(n+3-(n-1))

2^(n+3-n+1)

2^(3+1)

2^4= 16 thousands of bacteria in each group

8 0

3 years ago

A cell phone provider offers a plan that costs $30 per month plus$0.20 per text message sent or received. A comparable plan c

Natalija [7]

Part a. is correct. It is 150.

Part b.
First plan: $30 + $0.20 per text
For 50 texts
$30 + 0.20 * 50 = $30 + $10 = $40
For 50 texts, the first plan costs $40

For 50 texts per month, the first plan is better because it costs only $40 instead of $60
Second plan: $60 no matter how many texts

4 0

4 years ago

Read 2 more answers

What is the ratio 15 to 35 written as a fraction in lowest terms?

KATRIN_1 [288]

3/7 - I got there by dividing the numerator and denominator each by 5

4 0

3 years ago

Read 2 more answers

PLEASE HELP

Tems11 [23]

QUESTION A

The given multiplication problem is

$\frac{39}{64} \times \frac{8}{13}$

Factor each term to obtain;

$\frac{13\times 3}{8\times8} \times \frac{8}{13}$

Cancel out the common factors to obtain;

$\frac{1\times 3}{8\times1} \times \frac{1}{1}$

Simplify to get;

$\frac{3}{8}$

QUESTION B

The given multiplication problem is

$\frac{2}{3}\times \frac{1}{5}\times \frac{4}{7}$

This the same as

$\frac{2\times 1\times 4}{3\times 5\times 7}$

This simplifies to;

$\frac{8}{105}$

QUESTION C

The given problem is

$\frac{3}{5}\times \frac{10}{12} \times \frac{1}{2}$

This is the same as

$\frac{3}{5}\times \frac{5}{6} \times \frac{1}{2}$

$=\frac{1}{1}\times \frac{1}{2} \times \frac{1}{2}$

This simplifies to

$=\frac{1}{4}$

QUESTION D.

The given expression is

$\frac{4}{9}\times 54$

Factor the 54 to obtain;

$\frac{4}{9}\times 9\times 6$

Cancel the common factors to get;

$\frac{4}{1}\times 1\times 6$

This simplifies to;

$=24$

QUESTION E

The given problem is

$20\times 3\frac{1}{5}$

Convert the mixed numbers to improper fraction to obtain;

$=20\times \frac{16}{5}$

$=4\times5 \times \frac{16}{5}$

Cancel the common factors to get;

$=4\times1 \times \frac{16}{1}$

$=64$

QUESTION F

The multiplication problem is

$11 \times 2 \frac{7}{11}$

Convert the mixed numbers to improper fractions to obtain;

$11 \times \frac{29}{11}$

Cancel out the common factors to get;

$=1 \times \frac{29}{1}$

Simplify;

$=29$

QUESTION G

The given problem is

$5\frac{1}{3}\times 5\frac{1}{8}$

Convert to improper fractions;

$=\frac{16}{3}\times \frac{41}{8}$

Cancel out the common factors to get;

$=\frac{2}{3}\times \frac{41}{1}$

$=\frac{82}{3}$

Convert back to mixed numbers

$=27\frac{1}{3}$

QUESTION H

The given expression is

$10\frac{2}{3} \times 1\frac{3}{8}$

Convert to improper fraction to get;

$\frac{32}{3} \times \frac{11}{8}$

Cancel common factors to get;

$=\frac{4}{3} \times \frac{11}{1}$

Simplify

$=\frac{44}{3}$

Convert back to mixed numbers;

$=14\frac{2}{3}$

7 0

3 years ago

A ladder 13 feet long rests against a vertical wall. If the bottom of the ladder slides away from the wall at the rate of 0.5 ft

rodikova [14]

Answer:7

Step-by-step explanation:I smart beleve. Me

8 0

4 years ago

(6x^3 + 4x^2 + 2x) ÷ 2xAnswer fast plz..​

(6x^3 + 4x^2 + 2x) ÷ 2xAnswer fast plz..