Question

(6x^3 + 4x^2 + 2x) ÷ 2xAnswer fast plz..​

Answer 1

$\large\underline{\sf{Solution-}}$

$\textsf{Given expression;}$

$\sf{( {6x}^{3} + {4x}^{2} + 2x) \div 2x}$

$\sf \longmapsto \frac{ {6x}^{3} + 4 {x}^{2} + 2x}{2x}$

$\sf \longmapsto \frac{ {6x}^{3} }{2x} + \frac{4 {x}^{2} }{2x} + \frac{2x}{2x}$

$\sf \longmapsto \frac{ {6 \times x \times x \times x} }{2 \times x} + \frac{4 \times x \times x}{2 \times x} + \frac{2 \times x}{2 \times x}$

$\sf \longmapsto (3 \times x \times x) + (2 \times x) + 1$

$\sf \longmapsto {3x}^{2} + 2x + 1 \: \: \: \red{ Ans.}$

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-32x^4 ÷ 8x^2 Solve urgent plz..

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Answer 2

refer to the attachment okay

mark me a brainlist answer I need only 1