Answer:
CUBIE MiniDrawer Bin
Explanation:
MiniDrawers comes in two configurations, and each fitting comes in one drawerslot. The MiniDrawer (1-6) comes with the most primary pocket dimensions. And we have the 18-tray MiniDrawer (1-8) comes with another dimensions in its basic form. You will in fact find various pocket dimensions like 1,2,3,4,6,12, and these comes within the 18-tray and 6-tray MiniDrawers. And they come in all the dispensing modes mentioned in the question. Hence, the above answer. The answer is clear from the options as well, and since it has the matrix mode as well apart from single dose mode and multi dose mode.
Answer:
hub is central computer.....True...
4. Only (ii)
<u>Explanation:</u>
The declaration of the array can be of two types:
1. int a[100];
2. int[] a = new int[100];
The general thing about an array is that whenever we want to undergo traversal in an array, we always have to start from the 0th position as the size of the array may be a whole number (let us say 10). So, to undergo traversal in an array, we start from 0 to n-1 (in this case 9) such that it covers the size of the array.
The size of an array can be finite or infinite. The general rule is it starts from 0 to n-1 where n is the size of the array. In the above example, the range of the index of the array will be 0 through 100 and not 1 through 100.
In total there are 32 keywords in the c programming language.
Answer:
Explanation:
#include<iostream>
#include<ctime>
#include<bits/stdc++.h>
using namespace std;
double calculate(double arr[], int l)
{
double avg=0.0;
int x;
for(x=0;x<l;x++)
{
avg+=arr[x];
}
avg/=l;
return avg;
}
int biggest(int arr[], int n)
{
int x,idx,big=-1;
for(x=0;x<n;x++)
{
if(arr[x]>big)
{
big=arr[x];
idx=x;
}
}
return idx;
}
int main()
{
vector<pair<int,double> >result;
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
int choice;
cin>>choice;
while(choice!=2)
{
int n,m;
cout<<"Enter N"<<endl;
cin>>n;
cout<<"Enter M"<<endl;
cin>>m;
int c=m;
double running_time[c];
while(c>0)
{
int arr[n];
int x;
for(x=0;x<n;x++)
{
arr[x] = rand();
}
clock_t start = clock();
int pos = biggest(arr,n);
clock_t t_end = clock();
c--;
running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;
}
double avg_running_time = calculate(running_time,m);
result.push_back(make_pair(n,avg_running_time));
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
cin>>choice;
}
for(int x=0;x<result.size();x++)
{
cout<<result[x].first<<" "<<result[x].second<<endl;
}
}
