Observing, Looking, Collecting, there are a few words for "gathering information with your eyes".
Answer:
The following are code in the Java Programming Language.
//define boolean type function
boolean isReverse(int ar[], int b[])
{
//declare integer type variable
int x;
//set the for loop
for (x=0; x < ar.length && ar[x] == b[ar.length-1-x]; x++);
return x == ar.length;
}
Explanation:
<u>The following are the description of the code</u>.
In the above code that is written in the Java Programming Language, we define the boolean data type function that is 'is Reverse()' and pass two array integer data type arguments that is 'ar', 'b' in the then, declare integer data type variable that is 'x'. Set the for loop that the boolean type value is true or false.
Noise usually means static.
First, convert feet to inches. The ' denotes foot measurement while the " denotes inches. Since there are 12 inches in a foot,
5'10" = (5*12) + 10 = 70 inches
6'8" = (6*12) + 8 = 80 inches
a.) The lower limit is 70 inches while the upper limit is 80 inches.
b.) First, divide 78 inches by 12. That would 6.5 or 6 and a half feet. Since half foot is 6 inches, the length of the couch is 6'-6"
c.) Since the couch is between the limits, yes it would fit the space.
Hi,
I changed your program using some of the concepts you were trying to use. Hopefully you can see how it works:
#include <string>
#include <iostream>
#include <sstream>
#include <vector>
#include <algorithm>
using namespace std;
int main()
{
short T;
cin >> T;
cin.ignore();
string str[100];
for(int i=0; i<T; i++)
{
getline(cin, str[i]);
}
for (int i = 0; i < T; i++)
{
stringstream ss(str[i]);
string tmp;
vector<string> v;
while (ss >> tmp)
{
// Let's capitalize it before storing in the vector
if (!tmp.empty())
{
transform(begin(tmp), end(tmp), std::begin(tmp), ::tolower);
tmp[0] = toupper(tmp[0]);
}
v.push_back(tmp);
}
if (v.size() == 1)
{
cout << v[0] << endl;
}
else if (v.size() == 2)
{
cout << v[0][0] << ". " << v[1] << endl;
}
else
{
cout << v[0][0] << ". " << v[1][0] << ". " << v[2] << endl;
}
}
return 0;
}