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rusak2 [61]
3 years ago
9

What is the factored form of 125a^6-64

Mathematics
2 answers:
zaharov [31]3 years ago
7 0

Answer:

(5a^2-4)(25a^4 + 20a^2+16)

Step-by-step explanation:

125a^6-64

WE can write 125 as 5^3

Also a^6 = (a^2)^3

64  can be written as 4^3

125a^6-64

5^3(a^2)^3-4^3

(5a^2)^3-4^3

Now we apply a^3 - b^3 formula

a^3 - b^3 = (a-b)(a^2 + ab+b^2)

a= 5a^2  and b = 4

Plug in the values in the formula

(5a^2)^3 - (4)^3 = (5a^2-4)((5a^2)^2 + (5a^2)(4)+4^2)

= (5a^2-4)(25a^4 + 20a^2+16)

WE factored it completely


SVETLANKA909090 [29]3 years ago
6 0
<span>(5a^2-4)*(25a^4+20a^2+16) is your answer</span>
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