9514 1404 393
Answer:
0
Step-by-step explanation:
The function is defined everywhere except at x=-6. The limit value is the function value at that point.
f(6) = (6^2 -36)/(6 +6) = 0/12 = 0
The limit of the function is 0 as x → 6.
Answer:
(x -6)^2 +(y -3)^2 = 2
Step-by-step explanation:
The midpoint (C) is the center of the circle:
C = ((5, 4) +(7, 2))/2 = ((5+7)/2, (4+2)/2) = (6, 3)
A circle with center (h, k) that goes through point (a, b) can be written as ...
(x -h)^2 +(y -k) ^2 = (a -h)^2 +(b -k)^2
Using the values for this problem, we get ...
(x -6)^2 +(y -3)^2 = (5 -6)^2 +(4 -3)^2
(x -6)^2 +(y -3)^2 = 2
X = -6y - 12
4x + 5y =-39
4x + 5y = -39
-4(-6y - 12) + 5y = -39
-4(-6y) + 4(12) + 5y = -39
24y + 48 + 5y = -39
29y + 48 = -39
29y = -87
y = -3
x = -6y - 12
x = -6(-3) - 12
x = 28 - 12
x = 6
(x, y) = (6, -3)
I have no clue ...I'm nt so good in maths
Answer:
x= 52
Step-by-step explanation: you have a 90 degree angle the other side would be 90 also. you take 90 and subtract 38 to get the missing value?
