The sequence is being multiplied by three for ever term.
If you multiply 1 by 3, the result will be 3. Keep on multiplying each term by three and you'll find that the 10th term is 729
Answer:
1
Step-by-step explanation:
Answer:
96m²
Step-by-step explanation:
Hello there!
The figure shown is an irregular figure so to make it easier we are going to split the irregular figure into two regular figures
A triangle with a height of 6 m and a base of 12 m
and a parallelogram with a base of 10m and a height of 6m
Now lets find the area of each individual shape
For the triangle:
The area of a triangle can be calculated using this formula
where b = base and h = height
Knowing the base and height all we have to do is plug in the values into the formula

so we can conclude that the area of the triangle is 36 m²
Now lets find the area of the parallelogram
The area of a parallelogram can simply be found my multiplying the base and height
so A = 10 * 6
10 * 6 = 60
so the area of the parallelogram is 60 m²
Finally we add the two areas together
60 + 36 = 96m²
Thus the area of the irregular figure is 96m²
Answer:
150 on the line
85 on the right corner
65 in the top corner
Step-by-step explanation:
Answer:
Quotient is
and remainder is 0.
Step-by-step explanation:
Given: 
To find: quotient and remainder
Solution:
In the given question,
Dividend = 
Divisor = 
![\frac{5x^4+5x^2+5}{x^2-x+1}\\=\frac{5(x^4+x^2+1)}{x^2-x+1}\\=\frac{5[x^2(x^2+1)+1]}{x^2-x+1}\\=\frac{5[x^2(x^2-x+x+1)+1]}{x^2-x+1}\\=\frac{5[x^2(x^2-x+1)+x^3+1]}{x^2-x+1}\\=\frac{5[x^2(x^2-x+1)+x(x^2)+1]}{x^2-x+1}\\=\frac{5[x^2(x^2-x+1)+x(x^2-x+1+x-1)+1]}{x^2-x+1}\\=\frac{5[x^2(x^2-x+1)+x(x^2-x+1)+(x^2-x+1)]}{x^2-x+1}\\=\frac{5[(x^2-x+1)(x^2+x+1)}{x^2-x+1} \\=5(x^2+x+1)](https://tex.z-dn.net/?f=%5Cfrac%7B5x%5E4%2B5x%5E2%2B5%7D%7Bx%5E2-x%2B1%7D%5C%5C%3D%5Cfrac%7B5%28x%5E4%2Bx%5E2%2B1%29%7D%7Bx%5E2-x%2B1%7D%5C%5C%3D%5Cfrac%7B5%5Bx%5E2%28x%5E2%2B1%29%2B1%5D%7D%7Bx%5E2-x%2B1%7D%5C%5C%3D%5Cfrac%7B5%5Bx%5E2%28x%5E2-x%2Bx%2B1%29%2B1%5D%7D%7Bx%5E2-x%2B1%7D%5C%5C%3D%5Cfrac%7B5%5Bx%5E2%28x%5E2-x%2B1%29%2Bx%5E3%2B1%5D%7D%7Bx%5E2-x%2B1%7D%5C%5C%3D%5Cfrac%7B5%5Bx%5E2%28x%5E2-x%2B1%29%2Bx%28x%5E2%29%2B1%5D%7D%7Bx%5E2-x%2B1%7D%5C%5C%3D%5Cfrac%7B5%5Bx%5E2%28x%5E2-x%2B1%29%2Bx%28x%5E2-x%2B1%2Bx-1%29%2B1%5D%7D%7Bx%5E2-x%2B1%7D%5C%5C%3D%5Cfrac%7B5%5Bx%5E2%28x%5E2-x%2B1%29%2Bx%28x%5E2-x%2B1%29%2B%28x%5E2-x%2B1%29%5D%7D%7Bx%5E2-x%2B1%7D%5C%5C%3D%5Cfrac%7B5%5B%28x%5E2-x%2B1%29%28x%5E2%2Bx%2B1%29%7D%7Bx%5E2-x%2B1%7D%20%5C%5C%3D5%28x%5E2%2Bx%2B1%29)
So, quotient is
and remainder is 0.