Answer:
The answer is "Option D".
Step-by-step explanation:
A line is a horizontal 1D-dimensional representation without any thickness and extends in every way. It sometimes is also known as the straight line. The line, which connects two planes lies simultaneously on both planes, that's why in this question only "option D" is correct.
Answer:

Step-by-step explanation:
<u><em>The correct question is</em></u>
what is the equation for a line passing through (-2,3) and perpendicular to y= -1/2<em>x</em>+1 ?
Remember
If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes are equal to -1)
The slope of the given line is m=-1/2
so
the opposite reciprocal is m=2
<em>Find the equation of the line in point slope form</em>

we have

substitute

<em>Convert to slope intercept form</em>

isolate the variable y



Answer:
Step-by-step explanation:
First use distributive property: a(b + c) = a*b + a*c
3n - 6 = -8(6 + 5n)
3n - 6 = 6 * (-8) + 5n *(-8)
3n - 6 = -48 - 40n
Now add 40n to both sides
3n - 6 + 40n = -48 - 40n + 40n
43n - 6 = -48
Now add 6 to both sides
43n - 6 + 6 = -48 + 6
43n = -42
n = -42 /43
Answer:
21
Step-by-step explanation:
14+7=21
25/3 ft/s is speed of the tip of his shadow moving when a man is 40 ft from the pole given that a street light is mounted at the top of a 15-ft-tall pole and the man is 6 ft tall who is walking away from the pole with a speed of 5 ft/s along a straight path. This can be obtained by considering this as a right angled triangle.
<h3>How fast is the tip of his shadow moving?</h3>
Let x be the length between man and the pole, y be the distance between the tip of the shadow and the pole.
Then y - x will be the length between the man and the tip of the shadow.
Since two triangles are similar, we can write

⇒15(y-x) = 6y
15 y - 15 x = 6y
9y = 15x
y = 15/9 x
y = 5/3 x
Differentiate both sides
dy/dt = 5/3 dx/dt
dy/dt is the speed of the tip of the shadow, dx/dt is the speed of the man.
Given that dx/dt = 5 ft/s
Thus dy/dt = (5/3)×5 ft/s
dy/dt = 25/3 ft/s
Hence 25/3 ft/s is speed of the tip of his shadow moving when a man is 40 ft from the pole given that a street light is mounted at the top of a 15-ft-tall pole and the man is 6 ft tall who is walking away from the pole with a speed of 5 ft/s along a straight path.
Learn more about similar triangles here:
brainly.com/question/8691470
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