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Lera25 [3.4K]
3 years ago
5

What is the factored form of this expression?

Mathematics
1 answer:
Naddika [18.5K]3 years ago
3 0

Answer:

(x+9)(x-9)

Step-by-step explanation:

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Hi pls, help me with this, I am giving 15 points 10 for answering the question and 5 for telling me what is Q1 meaning and Q2 me
stepladder [879]

Answer:

we have to put the numbers in order..

(121,122,125, 126,132),M,(135,136,136,138,140)

Step-by-step explanation:

minimum : (smallest number) = 121

Q1 : 125

Q2 (median) : (132 + 135) / 2 = 267/2 = 133.5

Q3 : 136

maximum : (largest number) = 140

I did this a long time ago so im not so sure

8 0
3 years ago
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916 round it to the nearest hundreds
dlinn [17]

Answer:

900

Step-by-step explanation:

9<u>1</u>6

1 is less than 5, so it rounds up to 900

8 0
3 years ago
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HELP ASAP!! WILL GIVE BRAINLIEST!! ANSWER ALL PLEASE!!
agasfer [191]

Answer:

B) and A)

Step-by-step explanation:

6 0
3 years ago
I don’t know how to do this
stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as x approaches the edges. For example,

g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}

has two pieces, 2x+5 and x^2-10, both of which are continuous by themselves on the provided intervals. In order for g to be continuous everywhere, we need to have

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)

By definition of g, we have g(-3)=2(-3)+5=-1, and the limits are

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1

\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1

The limits match, so g is continuous.

For the others: Each of the individual pieces of f,h are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.

4 0
3 years ago
-4 + 6g, for g = 4 i need in a sentence
laiz [17]

Answer:

-4+6*4 = 20

Step-by-step explanation:

If g is equal to 4 the answer is 20

8 0
3 years ago
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