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marishachu [46]
4 years ago
11

How do i solve these?

Mathematics
1 answer:
Cloud [144]4 years ago
4 0
Do the top equation and that fraction line means devide so u devide the answers u get for the top and bottom
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Let f(x)=x−4<br> and g(x)=−2x+4<br><br> Find g(f(2))<br><br> 0<br><br> −12<br><br> 8<br><br> −8
marin [14]

Answer:

8

Step-by-step explanation:

This one is similar to the other one done with graphs , the only difference is we have equations instead of graphs.

Like the other one, we want to find f(2) and whatever that equals we plug into g(x) to find g(f(2))

So first lets find f(2)

f(x) = x - 4

f(2) = 2 - 4

f(2) = -2

g(f(2)) , f(2) = -2 , g(-2)

now lets find g(-2)

g(x) = -2x + 4

g(-2) = -2(-2) + 4

multiply -2 and -2 to get 4

g(-2) = 4 + 4

add 4 and 4 to get 8

g(-2) = 8

We can conclude that g(f(2)) = 8

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3 years ago
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Answer:

One slice of pizza will be 56.5486677646 cm long.

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Vertical and Adjacent Angles (3 Activities)<br> 100 POINTS+BRAINLIEST
Yakvenalex [24]

Answer:

Problem B: x = 12; m<EFG = 48

Problem C: m<G = 60; m<J = 120

Step-by-step explanation:

Problem B.

Angles EFG and IFH are vertical angles, so they are congruent.

m<EFG = m<IFH

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x = 12

m<EFG = m<IFH = 48

Problem C.

One angle is marked a right angle, so its measure is 90 deg.

The next angle counterclockwise is marked 30 deg.

Add these two measures together, and you get 120 deg.

<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.

Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.

m<G = 180 - 120 = 60

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3 years ago
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Korvikt [17]

Answer:

C. y=11

Step-by-step explanation:

6y-6=4y+16

6y=4y+22

2y=22

y=11

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3 years ago
A training field is formed by joining a rectangle and two semicircles. The semicircles are attached on opposite sides of the rec
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Step-by-step explanation:

There is figures in you question. Please check your question.

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