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ANEK [815]
3 years ago
11

These polygons are similar. Compare the first polygon to the second. Find the ratio of the areas..

Mathematics
1 answer:
Shtirlitz [24]3 years ago
4 0

Answer:

D

Step-by-step explanation:

For similar polygons, there exists a scale factor between side lengths. The scale factors of their areas will be the scale factor squared.

For example, a two similar rectangles with lengths 2 cm and 4 cm and widths 5 cm and 10 cm, The rectangles have a scale factor pf 2.  The rectangles also will have areas 10 and 40. The scale factor of their areas is 4 or 2 squared.

The polygons here have a scale factor of \frac{40}{15} =\frac{8}{3} and is simplified to 8/3. Their areas will be 8/3 squared or 64/9.

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Solve 2(x – 11)2 = 128.
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Answer:

Step-by-step explanation:

Multiply the numbers     2 ( x - 11 ) * 2 = 128

                                          4 ( x - 11 ) = 128

Distribute              4 ( x - 11 ) = 128

                                 4x - 44 = 128

Add 44 to both sides              4x - 44 = 128

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Simplify                        - Add the numbers    

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                                  4x = 128 + 44

                                   4x = 172

Divide both sides by the same factor                    4x = 172

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Simplify

-     Cancel terms that are in both the numerator and denominator

                                                                4x/4 = 172/4

                                                                     x = 172/4

-Divide the numbers

                                                           x = 172/4

                                                             x = 43

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