How do u make this 3/3
1 answer:
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Answer:
a) 99.84% probability that during a year, you can avoid catastrophe with at least one working drive
b) 99.999744% probability that during a year, you can avoid catastrophe with at least one working drive
Step-by-step explanation:
For each disk drive, there are only two possible outcomes. Either it works, or it does not. The disks are independent. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
4% rate of disk drive failure in a year.
This means that 96% work correctly,
a. If all your computer data is stored on a hard disk drive with a copy stored on a second hard disk drive, what is the probability that during a year, you can avoid catastrophe with at least one working drive?
This is when
We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So
We want . So
In which
99.84% probability that during a year, you can avoid catastrophe with at least one working drive
b. If copies of all your computer data are stored on four independent hard disk drives, what is the probability that during a year, you can avoid catastrophe with at least one working drive?
This is when
We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So
We want . So
In which
99.999744% probability that during a year, you can avoid catastrophe with at least one working drive
Answer:
Range = 115$
Standard Deviation = 43.76$
Variance = 1915.142$
Option A) The measures of variation are not very useful because when searching for a room, low prices, location, and good accommodations are more important than the amount of variation in the area.
Step-by-step explanation:
We are given the data for prices in dollars for one night at different hotels in a certain region.
234, 160, 119, 131, 218, 207, 146, 141
Range:
Sorted data: 119, 131, 141, 146, 160, 207, 218, 234
Standard Deviation:
where are data points,
is the mean and n is the number of observations.
Sum of squares of differences = 4160.25 + 90.25 + 2550.25 + 1482.25 + 2352.25 + 1406.25 + 552.25 + 812.25 = 13406
Variance =
Measure of variance for someone searching for room:
Option A) The measures of variation are not very useful because when searching for a room, low prices, location, and good accommodations are more important than the amount of variation in the area.