Roger is having a picnic for 78 guests. He plans to serve each guest at least one hot dog. If each package, p, contains eight hot dogs, which inequality could be used to determine how many packages of hot dogs Roger will need to buy?

1) $p \geq 78$

2) $8p \geq 78$

3) $8 +p \geq 78$

4) $78 + p \geq 8$

Answer:

2) $8p \geq 78$

Step-by-step explanation:

Given:

Number of guest in the picnic = 78 guest

Number of hot dog each guest will have = 1

Number of hot dogs in each package = 8 hot dogs.

We need to write the In equality used to determine the number of packages of hot dogs roger must buy

Solution:

Let the number of packages be 'p'.

First we will find the total number of hot dogs required.

so we can say that;

total number of hot dogs required is equal Number of guest in the picnic multiplied by Number of hot dog each guest will have.

framing in equation form we get;

total number of hot dogs required = $78\times 1 =78$

Now we can say that;

Number of hot dogs in each package multiplied by number of packages should be greater than or equal to total number of hot dogs required.

framing in equation form we get;

$8p\geq 78$

Hence The In equality used to determine the number of packages of hot dogs roger must buy is $8p\geq 78$ .

6 0

3 years ago

What is 4+2 x { 16/ (5+3)} 2

Dahasolnce [82]

The answer for you problem is 6

4 0

3 years ago

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An organization has members who possess IQs in the top 4% of the population. If IQs are normally distributed, with a mean of 100

murzikaleks [220]

Answer:

The minimum IQ score will be "126".

Step-by-step explanation:

The given values are:

Mean

$\mu = 100$

Standard deviation

$\sigma=15$

Now,

⇒ $P(z>x)=4 \ percent \ i.e., 0.04$

⇒ $P(z>\frac{x- \mu}{\sigma} )=0.04$

⇒ $1-P(z \leq \frac{x-100}{15})=0.04$

⇒ $\frac{x-100}{15}=z0.96$

$=NORMDIS(z=0.96)$

$=1.751$

⇒ $x=100+15\times 1.751$

$=126.265 \ i.e., 126$

7 0

2 years ago

Given that a=4 and b=5. evaluate : a²+3b

andreev551 [17]

Answer:

Step-by-step explanation:

4 squared is 16, and 5 times 3 is fifteen if you add them you get 31

3 0

3 years ago

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