Spencer would be the correct one because it's easier to keep your variables positive when trying to solve. Therefore, in order to keep the variable positive, one would have to add 4x to both sides.
Y ^(-2/3)^-6 = y^12/3 = y^4
x^(1/2)^ -6 = x^-3 = 1 x^3
so the answer is y^4 * 1 /x^3 = y^4 / x^3
A
Let us denote the number of tiles by
.
In the first store, if Darin bought
tiles, he would need to spend:
(measured in $)
In the second store, if Darin bought
tiles, he would need to spend:
(measured in $)
For the cost to be the same at both stores, it means (measured in $)
Moving
over to the left hand side and changing signs:
tiles
Let's check. If he buys 60 tiles in the first store, he spends:
$0.79×60 + $24 = $47.40 + $24 = $71.40
If he buys 60 tiles in the second store, he spends:
$1.19×60 = $71.40
∴
Darin needs to buy 60 tiles for the cost to be the same at both stores.