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Ann [662]
3 years ago
12

When A (squared) + A-3 is subtracted from 3a (squared) -5, the result is...

Mathematics
2 answers:
ioda3 years ago
6 0
(a^2+a-3)-(3a^2-5)= -2a^2+a+2

C.  is the answer 

Hope it helps.
yuradex [85]3 years ago
5 0
Answer is A) 2a (squared) -a-2

3a^2 - 5 - (a^2 + a -3) 
=3a^2 - 5 - a^2 - a + 3
=2a^2 - a -2 
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Simplify 9 − (−4).<br><br> −13<br> −5<br> 5<br> 13
andrew11 [14]
- - = +   9-(-4)= 9+4 so minus minus becomes plus. and 13 is the answer.
8 0
3 years ago
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dem82 [27]

Answer:

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The ans is in the picture with the  steps how i got it

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Step-by-step explanation:

4 0
3 years ago
You are planning your week-end schedule. You can spend at most 8 hours playing video games and doing homework. You want to spend
MatroZZZ [7]

The system of inequalities is:

v + h ≤ 8

v < 2

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<h3>Which system of equations represents this situation?</h3>

Let's define the variables:

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The maximum time that you can spend on both activities is 8 hours, then:

v + h ≤ 8

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You want to spend at least, 1.5 hours on homework, so:

h ≥ 1.5

Then the system of inequalities is:

v + h ≤ 8

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7 0
2 years ago
I need help solving this w/ steps please
Leya [2.2K]
The answer to this question is 0.527
3 0
4 years ago
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A company developed the following linear model to help budget annual expenses over time. In this model, x represents the number
ollegr [7]
The only reasonable answer I could think for this is "A.<span>The company's expense budget for 2009 was $189,785."
I believe this because since x is the years after 2009 then you wouldn't times that by the expense budget for that year or any year eliminating B and C. When finding the total expense budget for this you would have to take in account the budget from 2009 so that would lead it to add 189,758. Since we are talking about after 2009 then D would be eliminated since 2008 is before 2009. 
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6 0
3 years ago
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