1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Basile [38]
3 years ago
8

Please help I am in class rn and I need this DONe

Mathematics
2 answers:
Leviafan [203]3 years ago
7 0

#4.

Quadrant I - top right: (+, +)

Quadrant II - top left: (-, +)

Quadrant III - bottom left: (-, -)

Quadrant IV - bottom right: (+, -)

#5.

a. (-6, -2) : (-, -) : III

b. (3, 8) : (+, +) : I

c. (1, -4) : (+, -) : IV

d. (-5, 6) : (-, +) : II

Hope this helps!

lora16 [44]3 years ago
6 0

pattern. quadrant

(- ,-). III

(+,+). I

(+,-). IV

(-,+). II

Step-by-step explanation:

PLS MARK BRAINLIEST

You might be interested in
He dot plots show the number of hours a group of fifth graders and seventh graders spent playing outdoors over a one-week period
garik1379 [7]

Answer:

The left side of the data looks similar to the right side in the seventh-grade data, but not in the fifth-grade data.

Step-by-step explanation:

In the seventh-grade data, we can split dots into two equal groups, one from 0 to 3 and the other one from 4 to 7. In the first group the dot distribution is {2, 2, 3, 5}. In the second group the dot distribution is {5, 3, 3, 1}. Then, the left side looks similar to the right side (they are symmetrical).

If we perform a similar division between dots for fifth-graders data, we obtain one group, from 1 to 4, which dot distribution is {2, 3, 1, 4}; and another group, from 5 to 8, which dot distribution is {5, 5, 2, 2}. Then, the left side doesn't look similar to the right side (they aren't symmetrical).

7 0
4 years ago
Following number in word form 345.065
tangare [24]

Answer:

three hundred and forty five and sixty five thousandths

Step-by-step explanation:

the 5 is in the thousandths place so the whole decimal number ends with thousandths

4 0
3 years ago
Read 2 more answers
factors of 212 like finding a common factor its really hard because the number is so high please please HELP ME!!!!!!!
lesya692 [45]
<span>1,2,4,53,106,212

-----------------------

</span>
6 0
3 years ago
Help? please do not answer randomly
klasskru [66]

Answer:

x = 4.5

Step-by-step explanation:

Given a segment joining the midpoints of 2 sides of a triangle, then

the segment is half the length of the 3rd side, that is

5x = 0.5 × 45 = 22.5 ( divide both sides by 5 )

x = 4.5

8 0
3 years ago
Solve the equation 4 sin (x +30°) = 2<br>for 0 &lt; x &lt; 365​
tatuchka [14]

>

4 \sin(x + 30)  = 2 \\  \sin(x + 30 ) =  \frac{2}{4}   \\  \sin(x + 30)  =  \frac{1}{2}  \\  \sin(x + 30)  =  \sin(30)  \\ x + 30 = 30 \\ x = 30 - 30 \\ x = 0

Hence, x = 0°, 180° and 360° <em><u>Ans</u></em>

3 0
3 years ago
Other questions:
  • Create a sequence with five terms based on the given information. a. A arithmetic sequence with a third term of 8 and a constant
    14·1 answer
  • The table shows a proportional relationship. What is the missing y-value? __________
    14·2 answers
  • Two Mechanics can assemble 10 bicycles in 8 hours, how many bicycles could one mechanic assemble in 8 hours
    11·1 answer
  • A phone company offers two monthly plans. Plan A costs $19 plus an additional $0.11 for each minute of calls. Plan B costs $10 p
    10·1 answer
  • The second statement is the ______ of the first​
    12·1 answer
  • A chef cooked 5 kg of mashed potatoes for a dinner party. If the guest ate only 1/12 of the amount he cooked. How much did the e
    6·1 answer
  • A + (B + C) = (A + B) + C <br> property
    5·2 answers
  • 13 and 14 <br><br> Please help ASAP<br><br> Extra 100 points
    12·1 answer
  • Select the fraction that is equivalent to 2/3
    6·1 answer
  • One positive number is one-fifth of another number. The difference between the two numbers is 144, find the numbers.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!