Answer:
a) nearest jump is JL = 1380 inches = 115ft
b) number of jumps in 1 mile N= 46 jumps
Step-by-step explanation:
Given that the jump length is proportional to the body length.
If 2 inch grasshopper can jump 40 inches.
JL = k(BL)
k = JL/BL
where JL = jump length = 40 inches
BL = Body length = 2 inches.
k = 40/2 = 20
The constant of proportionality is 20.
For the athlete :
BL = 5ft 9 inches = 5(12)+9 = 69 inches.
The jump length of the athlete is:
JL = k(BL) = 20(69)
JL = 1380 inches. = 115ft
The number of jumps in 1 mile is
1 mile = 63360 inches
N = 63360/1380
N = 45.9 = 46
N= 46
Therefore, 46 jumps would be needed.
Answer:
Yes.
Step-by-step explanation:
A median i am 100% sure and i am in 11th grade so I can’t be wrong ;)
Answer:
x > 4
Step-by-step explanation:
3x - 7 > 5
3x - 7 + 7 > 5 + 7
3x > 12
x > 4
(2x² - 5) - (3x² + 4).
Pretend that there is a -1 in front of :(3x² + 4).
(2x^2-5)-1(3x^2+4)
2x^2-5-3x^-4
2x^2-3x^2-5-4
=-x^2-9
Answer: -x^2-9
