Answer:
(A) Similar triangles
Step-by-step explanation:
It is given that AB is parallel to DE, therefore ∠CAB=∠DEC=65°(Alternate angles),
Then from ΔACB and ΔDCE, we have
∠CAB=∠DEC=65°(Alternate angles)
and ∠ACB=∠DCE=50°(Vertically opposite angles)
Thus, by AA similarity, ΔACB is similar to ΔDCE.
Hence, option A that is similar triangles is correct.
