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Tom [10]
3 years ago
5

Ariel completed the work below to show that a triangle with side lengths of 9, 15, and 12 does not form a right triangle. mc018-

1.jpg Is Ariel’s answer correct? No, Ariel should have added 122 and 1
Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
3 0

Answer:

Ariel answer is wrong.

Step-by-step explanation:

Given that Ariel had done a Math problem for a triangle with sides

9,15 and 12.  She concluded that these sides are not that of a right triangle.

To check whether Ariel is right:

Greater side = 15

Hence greatest angle will be opposite 15

Let us check pythagorean theorem

smaller sides are 9 and 12

Square and add them

9 square +12 square = 81+144 = 225 =15 square

We find that Pythagorus theorem is satisfied

Hence it is concluded that the triangle is right angled and Ariel was wrong

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The outlier, 78, is removed from the data set shown. 23, 23, 25, 27, 34, 34, 35, 41, 45, 45, 78 How does this affect the range?
KATRIN_1 [288]
Hello.

The range with 78 is 55

without 78 is 22

So the range goes down 

Have a nice day
6 0
3 years ago
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The height of a triangle is two more than three times the base. Determine the dimensions that will give a total area of 28 yards
jonny [76]
H = 3b+2
A = (h*b)/2     28 = (3b+2)b/2     56 = 3b²+2b    0 = 3b² + 2b - 56

⊕\left \{ {{y=2} \atop {x=2}} \right.  \int\limits^a_b {x} \, dx  \lim_{n \to \infty} a_n   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]  \beta  \\  \\  \\  x^{2}  \sqrt{x}  \sqrt[n]{x}  \frac{x}{y}  x_{123}  x^{123}  \leq  \geq  \pi  \alpha   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]  x_{123}  \int\limits^a_b {x} \, dx  \left \{ {{y=2} \atop {x=2}}
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8 0
3 years ago
Which of the following explains why f(x) = log2x
Radda [10]

Answer:

  • There is no power of 2 that is equal to 0.
  • Its inverse does not have any x-intercepts.

Step-by-step explanation:

Given the function

\:\:f\left(x\right)=\log \:_2\left(x\right)

This function can be written as:

y=\log _2\left(x\right)

As the rule tells s that

\:y=log_ax\Rightarrow \:a^y=x

so

x=2^y\:\:

As we know that the value of x=0 at y-intercept.

0=2^y\:\:

For any value of y, this statement is false as there is no power of 2 that is equal to 0.

Also

Lets interchange x and y in the equation x=2^y\:\:  to find the inverse of the function.

y=2^x\:\:

So, it doesn't have any x-intercepts as for any value of x, the value of y can not be zero for this function.

Therefore, Its inverse does not have any x-intercepts.

3 0
3 years ago
An artist sells drawings. Each materials that he uses cost $30. He sells his drawings for $90. If he spends $600 for advertiseme
Delvig [45]

Answer:

Step-by-step explanation:

I believe it is 10 since he in total makes 60$ a drawing because 90- the 30$ for the material. So 60$ in profit is 600/60 which is 10 so he would need 10 drawing I believe hope this helps!

7 0
3 years ago
In any given season, a soccer team plays 65% of their games at home. When the team plays at home, they win 83% of their games. W
kodGreya [7K]

Answer:

29.9%

Step-by-step explanation:

We have that 65% of the games are at home, therefore 35% (100 - 65) are away from home.

We have that at home, they win 83% of the matches, therefore 17% (100 -83) lose them.

Also away from home they win 26% of the games, which means that 74% (100 -26) lose them.

We are asked that if the team does not win the game, find the probability that the game was played at home.

Then the favorable cases would be that he has played at home and that he has lost, that is, 65% (home games) and 17% (lost at home), the probability would be:

65% * 17% = 0.1105

Now, the probability that he loses, either at home or away from home, would be the sum of the previous probability plus when he loses away, which would be 35% of the away games, the 74% who are the losers, is say:

74% * 35% = 0.259

Therefore the probability would be:

0.1105 / (0.259 + 0.1105) = 0.299

Which means 29.9%

8 0
3 years ago
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