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Andrews [41]
3 years ago
6

Is 3+9 rational or irrational?​

Mathematics
1 answer:
zzz [600]3 years ago
5 0

Answer:

I Think 3+9 is irrational

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I NEED HELP ASAP!!
Levart [38]

Answer:

If i'm correct it would be 120 or 600.

Step-by-step explanation:

5 0
3 years ago
The question is in the picture
MakcuM [25]

Answer:

A

Step-by-step explanation:

If you divide 180 by 60 you can see that they send 3 texts a minute after you divide 45 by three and see that they have 15 minutes left the Number line diagram shows the amount of time and texts she can send.

4 0
4 years ago
Which shows all the like terms in the expression? <br><br> 4x -3+7x + 1
vaieri [72.5K]

Answer:

4x and 7x; -3 and 1: these are like terms

Step-by-step explanation:

when finding like terms, look for same variables.

6 0
3 years ago
Read 2 more answers
We are conducting a hypothesis test to determine if fewer than 80% of ST 311 Hybrid students complete all modules before class.
Juli2301 [7.4K]

Answer:

z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124  

Null hypothesis:p\geq 0.8  

Alternative hypothesis:p < 0.8  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis:p\leq 0.8  

Alternative hypothesis:p > 0.8

p_v =P(Z>2.124)=0.013  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation  

n=110 represent the random sample taken

X=97 represent the students who completed the modules before class

\hat p=\frac{97}{110}=0.882 estimated proportion of students who completed the modules before class

p_o=0.8 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v{/tex} represent the p value (variable of interest)  2) Concepts and formulas to use  We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.8 or 80%:  Null hypothesis:[tex]p\geq 0.8  

Alternative hypothesis:p < 0.8  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis:p\leq 0.8  

Alternative hypothesis:p > 0.8

p_v =P(Z>2.124)=0.013  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

5 0
4 years ago
There are 18 students in Mr.Alvarez’s art class. Throughout the year, every student must pair up with every other student to com
earnstyle [38]
If there are 18 students every one of the will pair up with 17 other students throughout the year so the total amount of pairs that can be made is 18x17=306 but since it’s not important if student A is paired with student B or student B with student A we should divide the total amount of pairs by two- 306:2=153 so in total there will be 153 projects finished
5 0
3 years ago
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