All categories

2 years ago

What are the x-intercepts of the quadratic function? f(x)=x^2+6x−27

Mathematics

2 answers:

masha68 [24]2 years ago

6 0

The x intercepts for this quadratic function is X = 3, and -9

Rasek [7]2 years ago

4 0

The x-intercepts are -9 and +3. What two number multiply to -27 but at to +6? +9 and -3. When you put x-9=0 and x+3=0, they both change their signs so what was +9 is not -9 and what was +3 was -3. I hope this helps you!

You might be interested in

The number of coffee shops in a certain country can be modeled by the quadratic function f(x)105x²+680x+4296, where f(x) is th

grigory [225]

A. X is the number of years after 2000

2006-200 = 6 years.

Replace x with 6 and solve:

105(6)^2 + 680(6) + 4296 = 12,156

Answer for part a: 12,156

Answer for part B.
There was just over 12,000 in 6 years , to get to 21,500 would be a little over 9,000 more 9/12 = 0.75

6 years x .75 = 4.5 years

6 + 4.5 = 10.5 years round to 10 years for estimating purposes

Answer for part b: about 10 years

7 0

1 year ago

Find the slope to Y = 5/2x-3

son4ous [18]

Answer:

slope = 5/2

Step-by-step explanation:

This equation is written in slope intercept form

y = mx+b where m is the slope and b is the y intercept

y = 5/2x -3

The slope is 5/2 and the y intercept is -3

5 0

3 years ago

Read 2 more answers

A school is planning to construct two rectangular play areas in the playground. The length of play area A must be 1 foot longer

Anna11 [10]

Answer:

А.The system has two solutions, but only one is viable because the other results in a negative width.

Step-by-step explanation:

Given

Let:

$L_A \to$ length of play area A

$W_A \to$ width of play area A

$L_B \to$ length of play area B

$W_B \to$ width of play area B

$x \to$ Area of A

$y \to$ Area of B

From the question, we have the following:

$L_A = 1 + 4W_A$

$W_B = 2 + W_A$

$L_B = 2 + 3W_B$

$x = y$

The area of A is:

$x = L_A * W_A$

This gives:

$x = (1 + 4W_A) * W_A$

Open bracket

$x = W_A + 4W_A^2$

The area of B is:

$y = L_B * W_B$

$y = (2 + 3W_B) * ( 2 + W_A)$

Substitute: $W_B = 2 + W_A$

$y = (2 + 3(2 + W_A)) * ( 2 + W_A)$

Open brackets

$y = (2 + 6 + 3W_A) * ( 2 + W_A)$

$y = (8 + 3W_A) * ( 2 + W_A)$

Expand

$y = 16 + 8W_A + 6W_A + 3W_A^2$

$y = 16 + 14W_A + 3W_A^2$

We have that:

$x = y$

This gives:

$W_A + 4W_A^2 = 16 + 14W_A + 3W_A^2$

Collect like terms

$4W_A^2 - 3W_A^2 + W_A -14W_A - 16 =0$

$W_A^2 -13W_A - 16 =0$

Using quadratic calculator, we have:

$W_A = -14.1$ or $W = 1.13$ --- approximated

But the width can not be negative; So:

$W = 1.19$

7 0

2 years ago

Will give, Branliest.<br><br>Thanks, <br>:)

Nikolay [14]

Answer:

250p-195

Step-by-step explanation:

did the quiz

8 0

2 years ago

Read 2 more answers

A pack of red pens can be divided into equal shares among 3, 5, 6 and 9 teachers with no pen left over?

Ugo [173]

Answer:

90 red pens

Step-by-step explanation:

we need to find the least common multiple of the numbers 3 , 5 , 6 , 9

6 = 2 × 3

9 = 3²

then

LCM(3,5,6,9) = 2×5×3² = 2×5×9 = 90

The number 90 can be divided into 3 ,5 ,6 ,9 with no remainder

Therefore the pack must have 90 pens or a multiple of 90

For example 180 , 270 ...

7 0

2 years ago