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Aleks04 [339]
3 years ago
13

What are the x-intercepts of the quadratic function? f(x)=x^2+6x−27

Mathematics
2 answers:
masha68 [24]3 years ago
6 0
The x intercepts for this quadratic function is X = 3, and -9
Rasek [7]3 years ago
4 0
The x-intercepts are -9 and +3. What two number multiply to -27 but at to +6? +9 and -3. When you put x-9=0 and x+3=0, they both change their signs so what was +9 is not -9 and what was +3 was -3. I hope this helps you!
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My friend recently proved 0=1 and i know something is wrong but i dont know what
konstantin123 [22]

Step-by-step explanation:

Remember when expanding radicals,

\sqrt{ab}  =  \sqrt{a}  \times  \sqrt{b}

When expanding radicals into two radicals, we don't let our radicand have two negative answers.

i  =  \sqrt{ - 1}

{i}^{2}  =  - 1

We don't do this

(\sqrt{ - 1} ) {}^{2}  =  \sqrt{ - 1 \times  - 1}

- 1 =  \sqrt{1}

- 1 = 1

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2 years ago
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3 years ago
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14x. ....................

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3 years ago
Help? I'd Appreciate it!
kondor19780726 [428]

<u>Answer</u>

y = (1/2)x - 1


<u>Explanation</u>

The first step is to get the gradient of the line.

The two points in the line are; (2,0) and (-2, -2).

Gradient = (-2 - 0)/(-2, - 2)

                = -2/-4

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To get the function we use one of the point (2,0) and a general point (x,y).

1/2 = (y - 0)/(x - 2)

1/2 = y/(x - 2)

(x - 2) = 2y

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Thank you for posting your question here at brainly. Feel free to ask more questions.   
<span>
The best and most correct answer among the choices provided by the question is </span><span>A. Between 0.05 and 0.01 </span> .    
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Hope my answer would be a great help for you.  </span>
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