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3 years ago

What common angle do acd and abe share

Mathematics

2 answers:

KiRa [710]3 years ago

4 0

Your answer would be ΔAED and ΔCDE

I hope I helped :)

- Shay❤

bixtya [17]3 years ago

4 0

Answer:

m∠BAE and m∠CAD

Step-by-step explanation:

we know that

In the triangle ABE the measure of angle m∠BAE is congruent to the measure of angle m∠CAD in the triangle ACD, because is a common angle

m∠BAE = m∠CAD -----> by common angle

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A study found that, in 2005, 12.5% of U.S. workers belonged to unions (The Wall Street Journal, January 21, 2006). Suppose a sam

Julli [10]

Answer:

There is not enough evidence to support the claim that union membership increased.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 400

p = 12.5% = 0.125

Alpha, α = 0.05

Number of women belonging to union , x = 52

First, we design the null and the alternate hypothesis

$H_{0}: p = 0.125\\H_A: p > 0.125$

The null hypothesis sates that 12.5% of U.S. workers belong to union and the alternate hypothesis states that there is a increase in union membership.

This is a one-tailed(right) test.

Formula:

$\hat{p} = \dfrac{x}{n} = \dfrac{52}{400} = 0.13$

$z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

Putting the values, we get,

$z = \displaystyle\frac{0.13-0.125}{\sqrt{\frac{0.125(1-0.125)}{400}}} = 0.3023$

Now, we calculate the p-value from the table.

P-value = 0.3812

Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept the null hypothesis.

Conclusion:

Thus, there is not enough evidence to support the claim that union membership increased.

8 0

2 years ago

Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id

Thepotemich [5.8K]

$\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

Explanation

$\frac{1}{a+bi}=c+di$

Step 1

multiplicate by the conjugate

$\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}$

notice that

$\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\ \end{gathered}$ $\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

I hope this helsp you

6 0

1 year ago

Plz guys help me In 2 please

Doss [256]

Answer:

Step-by-step explanation:

OMG!!!!! why don't you just SAY YOU WANT a BLEEPING REFLECTION!!!

I had to search through a slew of your questions to get clues as to what to do.

To reflect over the x axis, just negate the y term and leave the x term as it is.

M becomes (2, -1)

N becomes (-3, -1)

P becomes (-1, -4)

7 0

2 years ago

It's really hard for me to understand what they are asking.

Gekata [30.6K]

Answer:

B is the correct answer

Step-by-step explanation:

Angles 1, 2, and 3 added together should make 180 degrees.

So, if angle 2 is 70 degrees, you subtract 70 from 180 (180-70=110) and you're left with 110 degrees.

Angle 1 and 3 add together should make 110 degrees which makes B the only true statement.

3 0

2 years ago

2.The number of tickets sold to a play for each showing is 78, 84, 87, 80, 91, 95, and 80.

Luden [163]

Answer:

$Min =78$

The maximum is :

$Max = 95$

Now we can calculate the median since the sample size os n =7 the median would be the middle value at the position 4 from the dataset ordered and we got:

$Median =84$

Now we can find the quartile 1 we analyze the first 4 values 78, 80,80, 84 and the first quartile would be:

$Q_1= \frac{80+80}{2}= 80$

Now we can find the quartile 3 we analyze the last 4 values 84,87, 91, 95 and the third quartile would be:

$Q_3= \frac{87+91}{2}=89$

And finally the 5 number summary would be:

$Min = 78, Q_1 = 80, Median=84, Q_3 = 89, Max=96$

Step-by-step explanation:

We have the following data given:

78, 84, 87, 80, 91, 95, and 80.

The first step is order the dataset on increasing way and we got:

78, 80,80, 84,87, 91, 95

We can begin finding the minimum value and for this case is:

$Min =78$

The maximum is :

$Max = 95$

Now we can calculate the median since the sample size os n =7 the median would be the middle value at the position 4 from the dataset ordered and we got:

$Median =84$

Now we can find the quartile 1 we analyze the first 4 values 78, 80,80, 84 and the first quartile would be:

$Q_1= \frac{80+80}{2}= 80$

Now we can find the quartile 3 we analyze the last 4 values 84,87, 91, 95 and the third quartile would be:

$Q_3= \frac{87+91}{2}=89$

And finally the 5 number summary would be:

$Min = 78, Q_1 = 80, Median=84, Q_3 = 89, Max=96$

5 0

3 years ago