Ask question

Ask question

All categories

-Dominant- [34]

4 years ago

14

in a polynomial function of degree 5, what is the maximum number of extreme that could be possible? (please explain with the ans

wer if possible!)

1 answer:

Katen [24]4 years ago

7 0

Answer:

4 maximum extrema

Step-by-step explanation:

5th degree means that it can change direction 5 times, therefore creating a maximum of 4 extrema

You might be interested in

Given the point and slope, write the equation of the line

Ratling [72]

7)

$\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-4}{6-1}\implies \cfrac{-5}{5}\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-4=-1(x-1) \\\\\\ y-4=-x+1\implies y=-x+5$

9)

$\bf (\stackrel{x_1}{-12}~,~\stackrel{y_1}{14})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-14}{6-(-12)}\implies \cfrac{-15}{6+12}\implies \cfrac{-15}{18}\implies -\cfrac{5}{6}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-14=-\cfrac{5}{6}[x-(-12)] \\\\\\ y-14=-\cfrac{5}{6}(x+12)\implies y-14=-\cfrac{5}{6}x-10\implies y=-\cfrac{5}{6}x+4$

7 0

3 years ago

Please help me if you can please

aleksandrvk [35]

Answer:

17. m=-1/2

18. m=-1

Step-by-step explanation:

6 0

3 years ago

Consider this equation. cos(theta) = (-2√5)/5. If theta is an angle in quadrant II, what is the value of sin(theta)? NO LINKS!!!

vlada-n [284]

In second quadrant sin and cosec are positive

$\\ \tt\hookrightarrow sin^2\theta=1-cos^2\theta$

$\\ \tt\hookrightarrow sin^2\theta=1-(\dfrac{-2\sqrt{5}}{5})^2$

$\\ \tt\hookrightarrow sin^2\theta=1-\dfrac{20}{25}$

$\\ \tt\hookrightarrow sin^2\theta=\dfrac{5}{25}$

$\\ \tt\hookrightarrow sin\theta=\dfrac{\sqrt{5}}{5}$

$\\ \tt\hookrightarrow sin\theta=\dfrac{1}{\sqrt{5}}$

5 0

3 years ago

Phil bought 700 shares of a company’s stock for $9.29/share. He pays a broker a commission of $18 to buy and sell stock. After o

Lelechka [254]

+ $0.61

Have a nice day.

5 0

4 years ago

I need some help with this question, I got a different answer.

N76 [4]

Answer:

The median is the middle number.

Step-by-step explanation:

You have to order the numbers from least to greatest, or greatest to least, and choose the number in the middle. Since there is an even number of values, you have to take the mean of the two middle numbers. I hope this helps.

5 0

3 years ago