9514 1404 393
Answer:
0
Step-by-step explanation:
If a=b, you are asking for a whole number c such that ...
c = √(a² +a²) = a√2
If 'a' is a whole number, the only whole numbers that satisfy this equation are ...
c = 0 and a = 0.
0 = 0×√2
The lowest whole number c such that c = √(a²+b²) and a=b=whole number is zero.
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√2 is irrational, so there cannot be two non-zero whole numbers such that c/a=√2.
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<em>Additional comment</em>
If you allow 'a' to be irrational, then you can choose any value of 'c' that you like. Whole numbers begin at 0, so 0 is the lowest possible value of 'c'. If you don't like that one, you can choose c=1, which makes a=(√2)/2 ≈ 0.707, an irrational number. The problem statement here puts no restrictions on the values of 'a' and 'b'.
Answer:
Yes
Step-by-step explanation:
So permiter is two*lengths plus 2*width of a shape.
Area is the length times the width.
For examplel if a square has a length of 2, and a width of 3 the permiteter is:
2*2+3*3=
4+9
=
13
On the other hand, area would be:
2*3
=
6
I hope this helps!
Answer:
Step-by-step explanation:
I think it’s b correct me if I’m wrong
A^2 - b^2 = (a - b)( a +b);
<span>cos^4x-sin^4x =( cos^2x + sin^2x )( cos^2x - sin^2x) = 1* cos2x = co2x.</span>
You could do 60-37 then that would give you 23. If that's what your looking for
