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2^2 , or 4
since the exponents have the same base, we can subtract the exponent of the numerator by the exponent in the denominator.
So 2^-3 - 2^-5 = 2^(-3-(-5)) = 2^2
The new exponent is 2 because -3-(-5) is equal to 2.
since the exponents have the same base, we can subtract the exponent of the numerator by the exponent in the denominator.
So 2^-3 - 2^-5 = 2^(-3-(-5)) = 2^2
The new exponent is 2 because -3-(-5) is equal to 2.
Using a geometric sequence, it is found that the approximate value of the car at the end of the 10th year will be given by:
A. $6,974.
<h3>What is a geometric sequence?</h3>A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.
The nth term of a geometric sequence is given by:
In which is the first term.
In this problem, the first term and the common ratio are given, respectively, by:
Hence the equation is:
At the end of the 10th year, the value will be of:
Hence option A is correct.
More can be learned about geometric sequences at brainly.com/question/11847927
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