For the point P(−19,18) and Q(−14,23), find the distance d(P,Q) and the coordinates of the midpoint M of the segment PQ.
5x+3y=-9
-2x+y=8
The first step is the trickery (and quite frankly, hardest to explain) part. You need to multiply one equation by a number that will create one variable to be the negative version of the other...(Confusing, right? Don't worry, I'll show you)
We are going to solve for X first.
We will multiply the second equation by -3
5x+3y=-9
-3(-2x+y)=(-3)8
Now simplify:
5x+3y= -9
6x-3y= -24
Now combine the two equations (add them together)
11x= -33
Divide by 11
X=-3
Now plug X in to one of the first equations:
5(-3)+3y= -9
-15+3y =-9
3Y= 6
Y= 2
So your final answer is:
x= -3
Y= 2
Hope this helps!
The answer is C. That would be ur answer
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Step-by-step explanation:
If PQRS is a quadrilateral inscribed in a circle, then the opposite angles of the quadrilateral are <u>supplementary</u><u>.</u>
y + 68° = 180° { being opposite angles of cyclic quadrilateral }
y = 180° - 68°
y = 112°
x + 82° = 180° { being opposite angles of cyclic quadrilateral }
x = 180° - 82°
x = 98°
Hope it will help :)❤
