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Inessa [10]
3 years ago
6

How do you write words to match the expression 24-(6+3)

Mathematics
2 answers:
vlabodo [156]3 years ago
7 0

Answer:

Add six and three and subtract it from twenty four and you will get 18.

Step-by-step explanation:

The given expression: 24-(6+3)

Number 24 in words is equal to twenty-four

Number 6 in words is equal to six

and the Number 3 in words is equal to three

then;

The symbol '-' in words is equal to subtract

The symbol  '+' in words is equal to add

The symbol '(' represents  in words is open parenthesis

and the symbol ')' in words is  close parenthesis.

then the given expression in word is:

Add six and three and subtract it from twenty four and you will get 18.


suter [353]3 years ago
3 0

Twenty-Four minus the quantity Six plus Three

Hope this Helps!!!

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Stells [14]

Answer:

If we round it to the nearest tenth, our answer would be,

C≈ 17.2 (answer choice C)

Step-by-step explanation:

We will have to use the Pythagorean Theorem to solve this. Since we are not looking for the hypotenuse, but rather the length of one of the legs, we will have to use this,

Let's plug in the values,

Simplify,

Since we know that the opposite of a square is the square root, we are going to apply it.

This tells us that the length of the missing leg would be,

C ≈ 17.2336879396

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3 years ago
Which number line shows the inequality n< - 1?
vichka [17]
The third number line on the picture
4 0
2 years ago
Triangle ABC is an equilateral triangle. Segment AD measures 18 inches.Which statements about the diagram are correct? Check all
Margaret [11]

Answer:

The correct answer is option C and D.

C). DC = 6√3

D). AC = 12√3

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
(08.07 HC)
andreev551 [17]

Answer:

\textsf{A)} \quad x=-2, \:\:x=\dfrac{5}{2}

\textsf{B)} \quad \left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

C)  See attachment.

Step-by-step explanation:

Given function:

f(x)=2x^2-x-10

<h3><u>Part A</u></h3>

To factor a <u>quadratic</u> in the form  ax^2+bx+c<em> , </em>find two numbers that multiply to ac and sum to b :

\implies ac=2 \cdot -10=-20

\implies b=-1

Therefore, the two numbers are -5 and 4.

Rewrite b as the sum of these two numbers:

\implies f(x)=2x^2-5x+4x-10

Factor the first two terms and the last two terms separately:

\implies f(x)=x(2x-5)+2(2x-5)

Factor out the common term  (2x - 5):

\implies f(x)=(x+2)(2x-5)

The x-intercepts are when the curve crosses the x-axis, so when y = 0:

\implies (x+2)(2x-5)=0

Therefore:

\implies (x+2)=0 \implies x=-2

\implies (2x-5)=0 \implies x=\dfrac{5}{2}

So the x-intercepts are:

x=-2, \:\:x=\dfrac{5}{2}

<h3><u>Part B</u></h3>

The x-value of the vertex is:

\implies x=\dfrac{-b}{2a}

Therefore, the x-value of the vertex of the given function is:

\implies x=\dfrac{-(-1)}{2(2)}=\dfrac{1}{4}

To find the y-value of the vertex, substitute the found value of x into the function:

\implies f\left(\dfrac{1}{4}\right)=2\left(\dfrac{1}{4}\right)^2-\left(\dfrac{1}{4}\right)-10=-\dfrac{81}{8}

Therefore, the vertex of the function is:

\left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

<h3><u>Part C</u></h3>

Plot the x-intercepts found in Part A.

Plot the vertex found in Part B.

As the <u>leading coefficient</u> of the function is positive, the parabola will open upwards.  This is confirmed as the vertex is a minimum point.

The axis of symmetry is the <u>x-value</u> of the <u>vertex</u>.  Draw a line at x = ¹/₄ and use this to ensure the drawing of the parabola is <u>symmetrical</u>.

Draw a upwards opening parabola that has a minimum point at the vertex and that passes through the x-intercepts (see attachment).

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2 years ago
A class contains 3 female and 9 male students. Find the probability that a student chosen at random is a male, and then a second
sammy [17]
9 +3 =  12 students

9 are male
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2nd = 8/11

3/4 * 8/11 = 6/11

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