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3 years ago

Find the sum of 20 + 14 + 8 + ... + (-70)

Mathematics

1 answer:

Tanya [424]3 years ago

5 0

Answer:

-400

Step-by-step explanation:

20 + 14 + 8 + ... + (-70) =

= (-6·1+26)+(-6·2+26)+(-6·3+26)+...+(-6·16+26) =

= -6·(1+2+3+...+16)+26·16 =

= -6·16·17/2+26·16 =

= -6·8·17+26·16 =

= -816+416 =

= -400

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Answer:

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3 years ago

A square has an area of 100m2. What is the length of each side? please help and explain!!!

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3 years ago

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3 years ago

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3 years ago

If angle 1 is 140°, then find the measure of the other angles.

Vlad [161]

<h2>Angles</h2>

<h3>If angle 1 is 140°, then find the measure of the other angles.</h3>

∠2 = 40°
∠3 = 40°
∠4 = 140°
∠5 = 140°
∠6 = 40°
∠7 = 40°
∠8 = 140°

Explanation:

The relationship between ∠1 and ∠2 are supplementary angles, so when you add up their measurements, it will become 180°. Simply subtract 180 and 140 to get the measure of ∠2. As well as ∠3, they're linear pairs. And they are also supplementary. To determine the measure of ∠6 and ∠7, notice the relationship between ∠2 and ∠6. As you noticed, it is corresponding angles. So they have the same measurement. If ∠2 = 40°, then ∠6 = 40°. As well as ∠7, because the relationship between ∠6 and ∠7 are vertical pairs. So the angle measurement of ∠7 is also 40°.

Meanwhile, the relationship between ∠1 and ∠4 are vertical pairs. It means they also have the same measurement. So ∠4 = 140°. The relationship between ∠1 and ∠5 are corresponding angles, so they also have the same measurement. If ∠1 = 140°, then ∠5 = 140°. The relationship between ∠1 and ∠8 are alternate exterior angles, and they also have the same measurement. If ∠1 = 140°, then ∠8 = 140°.

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2 years ago