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Anton [14]
3 years ago
15

Please help solve, Algabra 1 Lesson 19

Mathematics
2 answers:
Westkost [7]3 years ago
6 0
Ok so ax + 3b = 2f
If you take '3b' away from both sides,
This means that ax = 2f -3b
And so once you divide both sides by a, you get:
x = (2f-3b)/a

Hope this helped
Helga [31]3 years ago
4 0
Ax+3b=2f
ax=2f-3b
x=2f-3b/a

Hope this helps!
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PLEASE ANSWER, WILL GIVE BRAINLIEST!
kumpel [21]
<h3>Answer:  b = 17</h3>

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Explanation:

The line must go through the point (5,2) which means x = 5 and y = 2 pair up together.

We'll plug these x and y values into the equation and solve for b.

y = -3x+b

2 = -3(5)+b

2 = -15+b

2+15 = b

17 = b

b = 17

The equation y = -3x+b turns into y = -3x+17

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3 years ago
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emmainna [20.7K]
The answer should be 32.
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What is 881,635 ÷ 20 and remainder plaese
Sonbull [250]

Answer:

44,081 R 15

Step-by-step explanation:


5 0
4 years ago
Read 2 more answers
Complete The Square:<br> (Z^2)-19z=66
Musya8 [376]
To solve the equation using complete square method we proceed:
z^2-19z=66
but
 c=(-b/2a)^2
c=(-19/2)^2
c=361/4
thus:
z^2-19z+361/4=66+361/4
factoring the LHS we get:
1/4(2z-19)^2=625/4

(2z-19)^2=625
getting the square root of both sides we get:
2z-19=+/-25
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8 0
3 years ago
ANSWER PLS URGENT VERY URGENT TYSM ik its a lot of questions but id really really be grateful for the help
anyanavicka [17]

Step-by-step explanation:

about circle R

arc angle MP = angle MRP = 78°

angle M = angle LMP.

according to the rules of inscribed angles, LMP is half of angle LRP.

LRP + MRP = 180° because together they cover the whole LM segment (half-circle).

LRP = 180 - MRP = 180 - 78 = 102°

so, LMP = angle M = 102/2 = 61°

also circle R (with arc ULNP)

the arc ULNP = arc UL + arc LN + arc NP = 160°

due to the congruent definition of JU and MP we know that arc UL = arc NP.

and we know arc LN = arc JM = 18°.

so,

160 = 2×arc NP + 18

142 = 2×arc NP

arc NP = 71° = arc UL

now, because arc MP + arc LP = 180 (half-circle),

arc MP = 180 - arc LP = 180 - arc LN - arc NP =

= 180 - 18 - 71 = 91°

about the circle R with 2 congruent chords :

the second answer : they are equidistant from R (the center of the circle).

about circle W

arc MK + arc KL = 180° (half-circle).

and we see

arc HL = arc KL = 53°.

so,

arc MK + 53 = 180°

arc MK = 180 - 53 = 127°

about circle M

arc QTS = 204°.

therefore, arc QRS = 360 - arc QTS = 360 - 204 =

= 156° = angle QMS.

according to the rules of inscribed angles

angle QTS = QMS/2 = 156/2 = 78°

4 0
2 years ago
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