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2 years ago

Please help solve, Algabra 1 Lesson 19

Mathematics

2 answers:

Westkost [7]2 years ago

6 0

Ok so ax + 3b = 2f
If you take '3b' away from both sides,
This means that ax = 2f -3b
And so once you divide both sides by a, you get:
x = (2f-3b)/a

Hope this helped

Helga [31]2 years ago

4 0

Ax+3b=2f
ax=2f-3b
x=2f-3b/a

Hope this helps!

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atroni [7]

Answer:

See below

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1 year ago

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d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

$LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}- Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A$

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$LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A - Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\$

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2 years ago

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strojnjashka [21]

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2 years ago

Factor the equation.

Kryger [21]

Hi!

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2 years ago

500=100(x-1)<br> Someone tell me step by step

Andre45 [30]

First, distribute the 100 to the (x-1) portion:
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then, add 100 to both sides of your equation to get “x” alone on the right side:
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next, divide 100x by 100 and 600 by 100 to isolate a singular “x”:
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2 years ago