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3 years ago

Xavier drove his car 70 miles with 7 gallons of fuel. How many more miles can he drive if he added 1 gallon of fuel?

Mathematics

2 answers:

strojnjashka [21]3 years ago

8 0

i think 10 more miles.

70/7=10

which means he gets 10 more miles for every gallon of fuel

SIZIF [17.4K]3 years ago

7 0

Answer:

10 more miles.

Step-by-step explanation:

If Xavier can drive his car 70 miles with 7 gallons of fuel, we have to use division.

70/7=10

So that means each 10 miles, he uses 1 gallon of fuel.

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SOLUTION

From the question, we are told that y varies inversely as x

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$\begin{gathered} y\propto\frac{1}{x} \\ \propto\text{ is a sign of proportionality } \end{gathered}$

Now, we will remove the proportionality sign and replace it with equal to sign =

If we do this, we will intoduce a constant k

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So we have the formula

$y=\frac{k}{x}$

We will substitute the values of x for 10 and y for 8 into the formula to get k, we have

$\begin{gathered} y=\frac{k}{x} \\ 8=\frac{k}{10} \\ k=8\times10 \\ k=80 \end{gathered}$

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$\begin{gathered} y=\frac{k}{x} \\ y=\frac{80}{x} \end{gathered}$

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3 years ago

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2 years ago

What is the solution set for 2x+5y>-1 and 4x-3<-3?

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PROBLEM ONE

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Solving for x in 2x + 5y > -1.

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Step 1 ) Subtract 5y from both sides.

2x + 5y > -1

2x + 5y - 5y > -1 - 5y

2x > -1 - 5y

Step 2 ) Divide both sides by 2.

2x > -1 - 5y

$\displaystyle\frac{2x}{2} > \displaystyle\frac{-1 - 5y}{2}$

$\displaystyle\ x > \frac{-1 - 5y}{2}$

So, the solution for x in 2x + 5y > -1 is...

$\displaystyle\ x > \frac{-1 - 5y}{2}$

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Solving for y in 2x + 5y > -1.

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Step 1 ) Subtract 2x from both sides.

2x + 5y > -1

2x - 2x + 5y > -1 - 2x

5y > -1 - 1x

Step 2 ) Divide both sides by 5.

5y > -1 - 1x

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$\displaystyle\ x > \frac{-1 -1x}{5}$

So, the solution for y in 2x + 5y > -1 is...

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PROBLEM TWO

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Solving for x in 4x - 3 < -3.

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Step 1 ) Subtract 3 from both sides.

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So, the solution for x in 4x - 3 < -3 is...

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- <em>Marlon Nunez</em>

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