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vazorg [7]
4 years ago
6

What is the domain of the function indicated on the coordinate plane?

Mathematics
1 answer:
Vesna [10]4 years ago
6 0

Domain deals with relations and functions:input>operation>output

A relation is a way to show how we can map one set of numbers to another.

The x coordinate will always be the input value. The y  coordinate will always be the output value.the domain of a relation  is the set of all allowable input values .

So to find the domain of the set  of ordered pairs all we need to do is to write  out the set of all the in put values  


So the answer to your question would  be your first choice, letter A.<em> {–3, –1, 0, 1, 2, 4}</em>


Hopes this help, have a great day, chao!!

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6 0
3 years ago
What is the value of x in the solution to the system<br> x+y=10<br> x-y=4
ANEK [815]

Answer:

x = 7; y = 3

Step-by-step explanation:

I used the Trial and Error Method and found that x = 7 and y = 3

=> 7 + 3 = 10

=> 10 = 10. ✔

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6 0
2 years ago
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7 0
3 years ago
Read 2 more answers
Show works please and do all of them for the 40 please because I need help
raketka [301]

Answer:

6 - Not similar

7 - Similar, 2x factor

8 - Similar, 3x factor

9 - Similar, 3x factor

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11 - Similar, 5/3x factor

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Step-by-step explanation:

8 0
3 years ago
Need help with this....
Yakvenalex [24]

Answer:

\boxed{\dfrac{f(a+h)-f(a)}{h}=-3a^2-3ah-h^2}

Step-by-step explanation:

f(x)=-x^3+2\\\\\dfrac{f(a+h)-f(a)}{h}\\\\f(a+h)\to\text{substitute x = a + h}\\f(a)\to\text{substitute x = a}\\\\\dfrac{f(a+h)-f(a)}{h}=\dfrac{-(a+h)^3+2-(-a^3+2)}{h}\\\\\text{use}\ (x+y)^3=x^3+3x^2y+3xy^2+y^3\\\\=\dfrac{-(a^3+3a^2h+3ah^2+h^3)+2-(-a^3)-2}{h}\\\\=\dfrac{-a^3-3a^2h-3ah^2-h^3+2+a^3-2}{h}\\\\\text{combine like terms}

=\dfrac{(-a^3+a^3)-3a^2h-3ah^2-h^3+(2-2)}{h}\\\\=\dfrac{-3a^2h-3ah^2-h^3}{h}\\\\=\dfrac{h(-3a^2-3ah-h^2)}{h}\\\\=-3a^2-3ah-h^2

6 0
3 years ago
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