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3 years ago

What is 6 8/15 as a percentage ( 6 and 8/15)

Mathematics

2 answers:

ivanzaharov [21]3 years ago

4 0

let's first off, convert the mixed fraction to improper fraction, and then to decimal and then to percent.

$\bf \stackrel{mixed}{6\frac{8}{15}}\implies \cfrac{6\cdot 15+8}{15}\implies \stackrel{improper}{\cfrac{98}{15}} \\\\\\ \stackrel{\textit{on to decimal}}{98\div 15\implies 6.5\overline{3}}\implies \stackrel{\textit{on to percent}}{6.5\overline{3}\cdot 100\implies 653.\overline{3}\%}$

Black_prince [1.1K]3 years ago

3 0

Answer:

6.53

Step-by-step explanation:

$6*15+8=98\\98/15\\6.53$

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Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,

omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

Pyramid A

$s = 4$ -- base sides

$V = 36$ -- Volume

Pyramid B

$s = 6$ --- base sides

Required

Determine the volume of pyramid B [Missing from the question]

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

$V = \frac{1}{3} * B * h$

Where B represents the area of the base equilateral triangle, and it is calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

$B = \frac{1}{2} * s^2 * sin(60)$

$B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}$

$B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}$

$B = 4\sqrt 3$

The height is calculated from:

$V = \frac{1}{3} * B * h$

This gives:

$36 = \frac{1}{3} * 4\sqrt 3 * h$

Make h the subject

$h = \frac{3 * 36}{4\sqrt 3}$

$h = \frac{3 * 9}{\sqrt 3}$

$h = \frac{27}{\sqrt 3}$

To calculate the volume of pyramid B, we make use of:

$V = \frac{1}{3} * B * h$

Since the heights of both pyramids are the same, we can make use of:

$h = \frac{27}{\sqrt 3}$

The base area B, is then calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where

$s = 6$

So:

$B = \frac{1}{2} * 6^2 * sin(60)$

$B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}$

$B = 9\sqrt 3$

So:

$V = \frac{1}{3} * B * h$

Where

$B = 9\sqrt 3$ and $h = \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9 * 27$

$V = 81$

6 0

3 years ago

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Neptune’s average distance from the sun is 4.503 x 10e9 km. Mercury’s average distance from the sun is 5.791 x10e9 km.about how

Igoryamba

Answer:

77.76 times

Step-by-step explanation:

The average distance of Neptune from the sun

= 4.503 × 10 ⁹ k m .

and Mercury = 5.791 × 10 ⁷ k m .

Hence neptune is ( 4.503 × 10 ⁹) ÷ (5.791 × 10 ⁷ ) times farther from the sun than mercury

i.e.( $\frac{4.503}{5.791}$ ) × 10⁹⁻⁷ times

= 0.7776 × 10 ² times

= 77.76 times.

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Answer:

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Answer:

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Step-by-step explanation:

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