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sasho [114]
3 years ago
14

Cindy has 68 more pokemon cards than Alfrdd. If Cindy has 150, how many does Alfred have?

Mathematics
2 answers:
Naddika [18.5K]3 years ago
5 0
Alfred will have 82 pokemon cards because this is a subtracting problem and Cindy has 68 more cards than Alfred so it will be 82
Y_Kistochka [10]3 years ago
3 0

Answer:

88

Step-by-step explanation:


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The more dvds the more the height incresases
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during their last game a football team lost a total of 12 yards on three consecutive plays. They lost the same number of yards o
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Theres 4 yards each play,

Step-by-step explanation:

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3 years ago
What are the solutions to the quadratic equation (5y +6) 2= 24?
boyakko [2]

Answer:

y=-2.18,-0.22

Step-by-step explanation:

We have been given the equation

(5y+6)^2=24

Take square root both sides. When ever we take square root, we include plus minus sign

\sqrt{(5y+6)^2}=\pm\sqrt{24}\\\\5y+6=\pm2\sqrt6

Now, subtract 6 to both sides of the equation

5y=-6\pm2\sqrt6

Divide both sides by 5

y=\frac{1}{5}(-6\pm2\sqrt6)

y=\frac{1}{5}(-6+2\sqrt6),y=\frac{1}{5}(-6-2\sqrt6)

In decimal we have

y=-2.18,-0.22



3 0
3 years ago
David is making a rectangular exercise yard for his turtle, Ralph. The perimeter of the yard is
marysya [2.9K]

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7 0
1 year ago
A code consists of two digit numbers chosen from 00-99 (i.E 00, 01, 02…..99) followed by two different letters of the alphabet.
Ede4ka [16]

Answer: 1/67600

Step-by-step explanation:

probability that the code is 43MZ:

Probability = (Total Required outcome / total possible outcomes)

Possible outcomes (digit) = (00,.............. ..., 99)

2.) possible outcomes (alphabet) = (A, B,............... .., Z)

P(43MZ) = P(43) × P(M) × P(Z)

P(43) = 1/100

P(M) = 1/26

P(Z) = 1/26

THEREFORE ;

P(43MZ) = (1/100) × (1/26) × (1/26) = 1/67600

4 0
3 years ago
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