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3 years ago

Dividing and multiplying complex numbers.

Mathematics

1 answer:

rusak2 [61]3 years ago

6 0

See attached picture for answers. Not 100% sure on the last one

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Write the equation of the line that passes through the points (-4,8) and (1,3)

Ksju [112]

Answer:

y = -x+4; Use the slope formula (y2-y1/x2-x1) and work backwards using that formula.

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3 years ago

Please help me. <br> What is 22% of 400?

Zolol [24]

Answer:

Step-by-step explanation:

you multiply 400 by 22 % = 88

400 x .22 = 88

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3 years ago

Read 2 more answers

N+5 - n-10=1 The n=5 and n-10 are in square root symbols

patriot [66]

$D:x\geq-5 \wedge x\geq10\\
D:x\geq10\\\\
\sqrt{n+5}-\sqrt{n-10}=1\\
\sqrt{n+5}=1+\sqrt{n-10}\\
n+5=1+2\sqrt{n-10}+n-10\\
2\sqrt{n-10}=14\\
\sqrt{n-10}=7\\
n-10=49\\
n=59$

7 0

3 years ago

Hey y'all can u help me on this

Mice21 [21]

Answer:

that's the picture,, but what is the question ??

8 0

3 years ago

Read 2 more answers

Find 9P9 and 9C9. Why do the answers differ?

sveta [45]

We have been given two expressions $9P9\text{ and }9C9$ . We are asked to find the value of each.

To find 9P9, we will use permutations formula.

$^nP_r=\frac{n!}{(n-r)!}$ , where

P = Number of permutations,

n = The total number of objects in the set,

r = Number of objects being chosen from the set.

$9P9=\frac{9!}{(9-9)!}$

$9P9=\frac{9\cdot 8\cdot 7\cdot 6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1}{(0)!}$

$9P9=\frac{362880}{1}$ Using $0!=1$

$9P9=362880$

To find 9C9, we will use combinations formula.

$^nC_r=\frac{n!}{r!(n-r)!}$ , where

C = Number of combinations,

n = The total number of objects in the set,

r = Number of objects being chosen from the set.

$9C9=\frac{9!}{9!(9-9)!}$

$9C9=\frac{9!}{9!(0)!}$

$9C9=\frac{9!}{9!\cdot 1}$ Using $0!=1$

Cancelling out $9!$ , we will get:

$9C9=\frac{1}{1}$

$9C9=1$

The answers differ because order. With permutations we care about the order of the elements, while with combinations we don't.

3 0

3 years ago