Question

HELPPP!!!!! Plzzzz!!

Answer 1

Given:

Cards labelled 1, 3, 5, 6, 8 and 9.

A card is drawn and not replaced. Then a second card is drawn at random.

To find:

The probability of drawing 2 even numbers.

Solution:

We have,

Even number cards = 6, 8

Odd numbers cards = 1, 3, 5, 9

Total cards =  1, 3, 5, 6, 8 and 9

Number of even cards = 2

Number of total cards = 6

So, the probability of getting an even card in first draw is:

$P_1=\dfrac{\text{Number of even cards}}{\text{Number of total cards}}$

$P_1=\dfrac{2}{6}$

$P_1=\dfrac{1}{3}$

Now,

Number of remaining even cards = 1

Number of remaining cards = 5

So, the probability of getting an even card in second draw is:

$P_2=\dfrac{\text{Number of remaining even cards}}{\text{Number of remaining total cards}}$

$P_2=\dfrac{1}{5}$

The probability of drawing 2 even numbers is:

$P=P_1\times P_2$

$P=\dfrac{1}{3}\times \dfrac{1}{5}$

$P=\dfrac{1}{15}$

Therefore, the probability of drawing 2 even numbers is $\dfrac{1}{15}$. Hence, the correct option is (b).