Question

PLEASE HELP!!!!!!!! y+1=1/3(x−3) how do i graph this? what are the points?

Answer 1

Step-by-step explanation:

You have the equation of a line in the point-slope form:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - point on a line

Convert the given equation to the slope-intercept form:

$y=mx+b$

m - slope

b - y-intercept (0, b)

$y+1=\dfrac{1}{3}(x-3)$         use the distributive property

$y+1=\dfrac{1}{3}x-1$          subtract 1 from both sides

$y=\dfrac{1}{3}x-2$

We only need two points to draw the line.

Choose two different x values. Put them in the line equation and calculate the y values:

for x = 0:

$y=\dfrac{1}{3}(0)-2=0-2=-2\to(0,\ -2)$

for x = 3:

$y=\dfrac{1}{3}(3)-2=1-2=-1\to(3,\ -1)$