ANSWER

EXPLANATION
The sum of an arithmetic sequence whose first term and last terms are known is calculated using

From the given information, the first term of the series is

and the last term of the series is

The sum of the first 26 terms is



Answer:
$36 400
Step-by-step explanation:
Step 1
The first step is to figure out how much money is saved at the end of each month for the period from January 1 to June 15. The amount deposited at the end of each month is obtained by multiplying the amount from the previous month by 3.
The amount deposited in January is 
The amount deposited in February is 
The amount deposited in March is 
The amount deposited in April is 
The amount deposited in May is 
The amount deposited in June is 
Step 2
The next step is to add up all the money that was deposited into the account. This calculation is shown below,

X = -1/4
Move the 1 to the other side then divide by 4 on both sides
Answer:
I am.
Step-by-step explanation:
Givens
D = 621 miles
r = 51.75
t = ?
Formula
d = r * t
Solve
621 miles = 51.75 * t Divide by 51.75
621 / 51.75 = t
t = 12 hours.
Answer B