I´d say "d" is the distance from the eye to the wall.
Now substracting 1.2-1 you´ll get the distance of the wall of the smallest triangle = 0.2 And you do 1.5-0.2= 0.3 that´s the distance of the wall of the other triangle. Then you solve everything with Pitagoras theorem. You have 2 rectangle triangles.
B+alfa=45°
tan^-1(0.2/d)=B
tan^-1(1.3/d)=alfa
THEN:
tan^-1(0.2/d)+tan^-1(1.3/d)=45°
Now you have 3 ecs and 3 variables.
alfa,B and "d"
Answer:
10
Step-by-step explanation:
Answer:

Step-by-step explanation:
Since, By the given diagram,
The side of the inner square = Distance between the points (0,b) and (a-b,0)


Thus the area of the inner square = (side)²


Now, the side of the outer square = Distance between the points (0,0) and (a,0),


Thus, the area of the outer square = (side)²

Hence, the ratio of the area of the inner square to the area of the outer square

Step-by-step explanation:
a) gradient= y2-y1/x2-x1
gradient of AB:
gradient=-4-1/2-3
=-5/-1
=5
gradient of BC:
=-5+4/7-2
=-1/5
b) as the priduct of both gradient is -1 ,both lines are perpendicular.
c) as we have seen lines are perpendicular so it is a right angled triangle.