ACCORDING TO QUESTION:-
Cucumbers = 6 for $2
Peppers = 12 for $9
Tomatoes = 6 fir $4
____________
SO NOW
____________
____________
For 9 cucumbers = as 6 cucumbers is for $2 then 9 will be of $3........1️⃣
For 18 peppers = as 12 peppers are for$9 so 18 will be of $12.........2️⃣
For 21 tomatoes =as 6 tomatoes are for $4 then 21 tomatoes are $14 .......3️⃣
Now add 1️⃣ +2️⃣ + 3️⃣
here $3 +$12 + $14= $29
HOPE IT HELPED YOU.
Answer: the answer is d trust me
Step-by-step explanation:
Honestly I don't know congruent so congrats I can't answer sorry
Answer:
15 nuts do not get found.
Step-by-step explanation:
Given that Of a squirrel's hidden nuts, for every 5 that get found, there are 3 that do not get found.
Total number of nuts squirrel had hidden = 40
Proportion of nuts not found to total = 3/(3+5) = 3/8
Hence out of 40, nuts not found =3/8(40) = 15 nuts.
15 nuts would not be found and 25 nuts would be found if squirrel had hidden in total 40 nuts.
This is because the proportion of found:unfound = 5:3
Hence 25:!5 =5:3 satisfies this
15 nuts are not found.
Answer:
The difference in the sample proportions is not statistically significant at 0.05 significance level.
Step-by-step explanation:
Significance level is missing, it is α=0.05
Let p(public) be the proportion of alumni of the public university who attended at least one class reunion
p(private) be the proportion of alumni of the private university who attended at least one class reunion
Hypotheses are:
: p(public) = p(private)
: p(public) ≠ p(private)
The formula for the test statistic is given as:
z=
where
- p1 is the sample proportion of public university students who attended at least one class reunion (
)
- p2 is the sample proportion of private university students who attended at least one class reunion (
)
- p is the pool proportion of p1 and p2 (
)
- n1 is the sample size of the alumni from public university (1311)
- n2 is the sample size of the students from private university (1038)
Then z=
=-0.207
Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.
