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Karolina [17]
2 years ago
5

Find the smallest 4 digit number which is exactly divisible by 72 and 108with explaination​

Mathematics
1 answer:
likoan [24]2 years ago
5 0

The smallest 4-digit number which is exactly divisible by 72 and 108 is 1080.

<h3>What is LCM?</h3>

The least common multiple that is divisible by both a and b is the smallest positive integer, lowest common multiple, or smallest common multiple of two numbers a and b, generally indicated by LCM.

The Least common multiple of both the numbers 72 and 108 is 216. Since 216 is the least common multiple of both the numbers. Therefore, the four-digit number needs to be a multiple of 216 to be divisible by both the numbers. Thus, when 216 is multiplied by 5 the result is 1080, which is divisible by both 72 and 108. Hence, the smallest 4-digit number which is exactly divisible by 72 and 108 is 1080.

Learn more about Least Common Multiple:

brainly.com/question/20739723

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Write 4.9 × 10–8 in decimal notation
34kurt

Answer:

0.000000049.

Step-by-step explanation:

This will have  7 zeros after the decimal point followed by 49:

4.9 × 10^–8 = 0.000000049.

If we imagine the decimal point making jumps to the right over the digits it takes 8 jumps till it gets to 4.9. that's where the -8 comes in.

7 0
3 years ago
The following set of ordered pairs represents a power inverse variation. Find the value of r given that k = 5.
pochemuha

Answer:

r=2

Step-by-step explanation:

y = k x^r  is the formula for a direct variation

y = k x^ -r is the formula for a indirect variation

20= 5 (1/2)^ -r

Divide each side by 5

4 = (1/2) ^ -r

Rewriting

2^2 = 2^ -1 ^ -r

2^2 = 2 ^ r

The bases are the same so

2 =r

4 0
3 years ago
The given line segment has a midpoint at (3, 1).
Katena32 [7]

Answer:

y=\frac{1}{3}x

Step-by-step explanation:

The given line segment has a midpoint at (3, 1) and goes through (2, 4), (3, 1), and (4, -2). We can use any two of the three points to calculate the equation of the line. Let us use the points (2, 4) and (4, -2)

Therefore the line goes through (2, 4) and (4, -2). The equation of a line passing through (x_1,y_1)\ and\ (x_2,y_2) is:

\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}.

Therefore the line passing through (2, 4) and (4, -2) has an equation:

\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}\\\frac{y-4}{x-2}=\frac{-2-4}{4-2}\\\frac{y-4}{x-2}=\frac{-6}{2}\\y-4=x-2(-3)\\y-4=-3x+6\\y=-3x+10

Comparing with the general equation of line: y = mx + c, the slope (m) = -3 and the intercept on the y axis (c) = 10

Two lines are said to be perpendicular if the product of their slope is -1. If the slope of line one is m1 and the slope of line 2 = m2, then the two lines are perpendicular if:

m_1m_2=-1.

Therefore The slope (m2) of the perpendicular bisector of y = -3x + 10 is:

m_1m_2=-1\\-3m_2=-1\\m_2=\frac{1}{3}

Since it is the  perpendicular bisector of the given line segment, it passes through the midpoint (3, 1). The equation of the perpendicular bisector is:

\frac{y-y_1}{x-x_1}=m\\\frac{y-1}{x-3}=\frac{1}{3}\\ y-1= \frac{1}{3}(x-3)\\ y-1=\frac{1}{3}x-1\\y=\frac{1}{3}x

the equation, in slope-intercept form, of the perpendicular bisector of the given line segment is y=\frac{1}{3}x

7 0
3 years ago
Read 2 more answers
SOMEONE PLEASE HELP! I'LL THANK YOU AND RATE 5 STARS AND MARK BRAINLIEST IF I CAN!!
viktelen [127]
Slope of AB=(2-3)/(1+1)=-1/2; AC=(-1-3)/(-3+1)=-4/-2=2; BC=(-1-2)/(-3-1)=-3/-4=3/4.
The product of two sides that are perpendicular is -1. Slopes of AB and AC are perpendicular so angle A is a right angle. ABC is a right-angled triangle.
8 0
3 years ago
What is 9x9x9x9x9x9x9x9x9x9x9x9x9x9x8?<br> Will upvote!
n200080 [17]
IDK         vhruvurvjrnedyjjnryghtfjdhvujrnhbyufj
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