9514 1404 393
Answer:
- square: 12 ft sides
- octagon: 6 ft sides
Step-by-step explanation:
This problem can be worked in your head.
If the perimeters of the square and regular octagon are the same, the side length of the 4-sided square must be the same as the length of 2 sides of the 8-sided octagon. Since the side of the square is 6 ft more than the side of the octagon, each side of the octagon must be 6 ft, and each side of the square must be 12 ft.
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We can let s represent the side length of the octagon. Then we have ...
8s = perimeter of octagon
4(s +6) = perimeter of square
These are equal, so ...
4(s +6) = 8s
s +6 = 2s . . . . . . divide by 4
6 = s . . . . . . . . . . subtract s
The octagon has 6-ft sides; the square has 12-ft sides.
You can get a circle by cutting horizontally and a hyperbola by cutting vertically. You can also get an ellipse and a parabola by cutting at an angle depending on whether the cut comes out the other side or not.
It will have a vertical asymptote when the denominator approaches zero.
2x-6=0
2x=6
x=3
So the vertical asymptote is the vertical line x=3
Answer:
Them all as he has to know how far he travels the customer rate to see is there is an increase of decrease price of gasoline to see if it's affecting g his outcome and price per miles for obvious reasons haha
Answer:
10
Step-by-step explanation:
h(x)=4x-2 h(x)=3
h(3)=4(3)-2 substitute
h(3)=12-2 multiply
=10 subtract
