One cat has four paws, so there are 120/4=30 cats. If a "set" of cats is two uncool cats and three cool cats, there are five cats in a set, so there are 30/5=6 sets. Since each of the six sets contains three cool cats, there are 18 cool cats in the family.
Answer:
log(32/125)
=log32 - log125 [log(x/y)=log(x) - log(y)]
=log(2)^2 - log(5)^3
=2log2-3log5 [log(x)^p=p log x]
=2a-3b
Standard algorithm i think
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12 laps because Lee ran 3 and that's half of what ray ran so times that by 2 and then times 6 by 2 and that's your answer
