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Harman [31]
3 years ago
8

Flying with a tailwind a plane averaged 158 km/h. On the return trip the plane averaged 112 km/h with same wind. Find wind &

plane speed in still air.
Mathematics
1 answer:
Roman55 [17]3 years ago
7 0

The key idea here is that

speed of plane in wind = (speed of plane in air) + (speed of wind)

Let s be the speed of the plane in still air, and w the wind speed. A tailwind blows in the same direction as the plane, so for the first leg of the trip, we have

158\,\dfrac{\rm km}{\rm h}=s+w

For the return trip, the wind would blow in the opposite direction:

112\,\dfrac{\rm km}{\rm h}=s-w

Solve this system and you'll find s=135\,\dfrac{\rm km}{\rm h} and w=23\,\dfrac{\rm km}{\rm h}.

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Answer:

a

Step-by-step explanation:

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3 years ago
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artcher [175]

Answer:

1 / 8², B

Step-by-step explanation:

8 / 8³

8³ = 8*8*8

So, the equation can also be written as:

8 / 8*8*8

divide the numerator and denominator by 8.

1 / 8*8

This is equal to:

1 / 8²

The answer is B.

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3 years ago
At a birthday party there were 20 balloons. A few of the kids decided to pop b balloons so the parents blew up another 6 balloon
notsponge [240]
The expression could be: (20-b)+6
5 0
3 years ago
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notsponge [240]

Option 3

The solution for given expression is \frac{(x - 4)(x - 4)}{(x + 3)(x + 1)}

<h3><u>Solution:</u></h3>

Given that we have to divide,

\frac{x^2 -16}{x^2 + 5x + 6} \div \frac{x^2 + 5x + 4}{x^2 -2x - 8}   ---- (A)

Let us first factorize each term and then solve the sum

Using a^2 - b^2 = (a + b)(a - b)

x^2 -16 = x^2 - 4^2 = (x + 4)(x -4)  ----- (1)

x^2 + 5x + 6 = (x + 2)(x + 3)   ----- (2)

x^2 + 5x + 4 = (x+1)(x + 4)   ---- (3)

x^2 -2x - 8 = (x-4)(x + 2)   ---- (4)

Now substituting (1), (2), (3), (4) in (A) we get,

\frac{(x + 4)(x -4)}{(x +2)(x +3)} \div \frac{(x+1)(x+4)}{(x-4)(x +2)}

To do division with fractions, we turn the second fraction upside down and change the division symbol to a multiplication symbol at the same time. Then we treat this as a multiplication problem, by multiplying the numerators and the denominators separately.

\frac{(x + 4)(x -4)}{(x +2)(x +3)} \times \frac{(x - 4)(x + 2)}{(x + 1)(x + 4)}

On cancelling terms we get,

= \frac{(x -4)(x-4)}{(x + 3)(x + 1)}

Thus option 3 is correct

6 0
4 years ago
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