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Alenkinab [10]
3 years ago
8

What is the quotient of Three-fourths and StartFraction 5 Over 6 EndFraction?

Mathematics
2 answers:
krok68 [10]3 years ago
8 0

Answer:

9/10 (look under here) or this = Three-fourths divided by one-eighth = 6 (D)

Step-by-step explanation:

For the first layer, Total = 1

Second layer:

1 is divided into 4 places = 1/4

So we have 1/4 in 4 places

The total of the second layer = 1/4×4 = 1

Third layer:

Each 1/4 is divided into 2 = 1/4÷2

= 1/4× 1/2 = 1/8

1/4 in 4 places = 1/8 in 2(4) places

= 1/8 in 8 places

Total of third layer = 1/8×8 = 1

Find attached the diagram derived from the above used in solving the question.

We are to find the fraction bars that represent the equation.

For those circled: 6 of the 1/8 in the third layer are under 3 of the 1/4 in the second layer.

Since under those circled, there are 6 boxes with 1/8, the fraction bar that would represent the equation would be equal to 6 in the left and right hand side of the equation.

The fraction bars that represent the equation = 3(1/4) ÷ 1/8

= 3/4 × 8/1 = 6

Therefore, Three-fourths divided by one-eighth = 6 (D)

Karo-lina-s [1.5K]3 years ago
5 0

Answer:

B) 9/10

Step-by-step explanation:

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5 0
3 years ago
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The expression that describes the rate of U.S. per capita sales of bottled water for the period 2007–2014 is:

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The definite integral of the expression from t=2 to t=6 is:

s(t) = 0.25t^2-t+29\\\int\limits^6_2 {s(t)} \, dt= \int\limits^6_2 {(0.25t^2-t+29)} \, dt\\\int\limits^6_2 {s(t)} \,dt= (\frac{t^3}{12} -\frac{t^2}{2}+29t +c)|^6_2 \\S(6) -S(2) = (\frac{6^3}{12} -\frac{6^2}{2}+29*6 +c) - (\frac{2^3}{12} -\frac{2^2}{2}+29*2 +c)\\S(6) -S(2) = 117.333\ gallons

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3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Substitute a for 6 and b for 2 to get 6^2+2^2=40

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7 0
2 years ago
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